Jim Popovitch wrote: >On Fri, Feb 22, 2008 at 4:03 PM, Mark Sapiro <[EMAIL PROTECTED]> wrote: >> You could try to find the line >> >> urlpat = re.compile(r'(\w+://[^>)\s]+)') # URLs in text >> >> near the beginning of Mailman/Archiver/HyperArch.py and change it to >> >> urlpat = re.compile(r'(\w+://[^>)\s]+?)\.?(\s|$)') # URLs in text > >Mark, that works well for the case I described. I did find something >else similar that doesn't work: > > this is another url http://www.yahoo.com, and so is this >http://www.google.com. > >Gets converted into: > this is another url <A >HREF="http://www.yahoo.com,";>http://www.yahoo.com,</A> > and so is this <A >HREF="http://www.ibm.com";>http://www.google.com</A>.
I assume that's a typo and 'ibm' should be 'google'. >So, the problem seems to appear with commas too which makes me wonder >if this can be resolved with this: > > urlpat = re.compile(r'(\w+://[^>)\s]+?)(\.|,)?(\s|$)') # URLs in text > >but then I got to thinking about any other punctuation make that >follows a URL... and my mind started spinning :-) I think the suggestion above - (\.|,)? would work for comma, but you could do it other ways - e.g. urlpat = re.compile(r'(\w+://[^>)\s]+?)[.,;]?(\s|$)') # URLs in text to handle '.', ',' and ';', and you could extend that with more characters, but you really need to be careful. Consider for example, <http://www.example.com/some/page#anchor.> which could be a valid URL ending in '.'. -- Mark Sapiro <[EMAIL PROTECTED]> The highway is for gamblers, San Francisco Bay Area, California better use your sense - B. Dylan ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org http://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://www.python.org/cgi-bin/faqw-mm.py Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: http://mail.python.org/mailman/options/mailman-users/archive%40jab.org Security Policy: http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq01.027.htp
