> -----Original Message----- > From: Odhiambo Washington [mailto:odhia...@gmail.com] > Sent: Monday, July 11, 2011 10:37 AM > To: Steff Watkins > Cc: Mailman Users List > Subject: Re: [Mailman-Users] Is there a Command to extract > the lists owners? > > > > On Mon, Jul 11, 2011 at 12:27, Steff Watkins > <s.watk...@nhm.ac.uk> wrote: > > > > I need to email each list owner to let them know the server > > will be off line while I upgrade it, so I need their > email addresses. > > > > regards > > Perhaps it would be nice if this command also listed the > listname against the owners?
It does. Use the -w option. This stuff is really easy to find out about. Just trying running the command with an option of '--help' . If the command doesn't recognise the option it will usually complain and stop working so no damage done there. However if the command (and I'm talking generally about unixy sort of commands, not just Mailman in particular).. If the command does recognise the '--help' option it wil... give you help! The '-h' option is usually good for this as well. If you're really tetchy about supplying unknown options to random binaries then do the operation as a standard or restricted user. Then you minimise the potential for any damage you might do. Simples! :) Steff ----- ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org http://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: http://mail.python.org/mailman/options/mailman-users/archive%40jab.org