>>> On 08/02/2015 at 15:00, <[email protected]> wrote: > Hi, > > We're running Mailman 2.1.12. We have a list that is largely moderated, > but there is a small group of posters who should not be. Because of the > size of the list the Membership management forms are a little cumbersome > for checking all of these. Is there command line method to get a list > of members who have their moderation flag either set, or unset if that's > easier? Alternatively, is there a way to list all the members of the > list with their moderation flag as part of the output? I did look > around a bit, but my google mojo is failing me... > > Thanks in advance for any help. You could do this with a small python script called via withlist At http://www.msapiro.net/scripts/ there are a lot of small utility scripts.
https://www.msapiro.net/scripts/set_mod.py sets or removes the flag for given members. If you already know the members to set moderated this would be the way to do it. https://www.msapiro.net/scripts/list_mod.py Lists the moderated on unmoderated members. Thats perhaps fullfills your wish best. ------------------------------------------------------ Mailman-Users mailing list [email protected] https://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: https://mail.python.org/mailman/options/mailman-users/archive%40jab.org
