I am trying to get the user to choose from 2 comboboxes...cant seem to get this
to work.......maybe someone out there can see something I am doin wrong?
I think this how it works? Using the code below
The user selects two values in combo boxes ("PriceFactor and PriceArea")
Click the button to call function "ReturnQueryResults"
The Array is built from the values of the two dropdown boxes ("id =
PriceFactor" and "id = PriceArea") using their ID values
The javascript call is made that calls Ajax page which sends the php page the
array of values. I then have to parse the ID (the array) with "Get" in the php
page, formatting the output, which is then shown on the target specified in the
Ajax page.
The results go back to the back to the ajax page
I don't have a great understanding of this...trying with a couple dropdowns to
start.
Any help would be greatly appreciated...I think I am pretty close but can use
another set of eyes...
THanks
HTML PAGE:
<p><b>Please Choose Price Factor:</b><br>
<select name="PriceFactor" id="PriceFactor">
<option value=""></option>
<option
value="greaterthan">Greater Than</option>
<option value="lessthan">Less
Than</option>
<option
value="between">Between</option>
<option value="equalto">Equal
To</option>
<option
value="greaterthanequalto">Greater Than Equal To</option>
<option
value="lessthanequalto">Less Than Equal To</option>
</select>
<p><b>Please Choose Area:</b><br>
<select name="PriceArea" id="PriceArea">
<option value=""></option>
<option value="100">100</option>
<option value="500">500</option>
<option value="700">700</option>
</select>
<input type="button" value="Send to Ajax and Tab"
onClick="ReturnQueryResults();">
<br>
<br>
<script type="text/javascript">
function ReturnQueryResults() {
var url = " PropertyQuery3?";
var input_values_to_append =
new Array('PriceFactor','PriceArea');
for(var i = 0; i <
input_values_to_append.length; i++) {
url +=
'&'+input_values_to_append[i].name+'='+input_values_to_append[i].value;
}
javascript:getResulthype('url')
}
</script>
AJAX Page:
function getResulthype(url){
var _target = 'content_details_form';
if (id.length == 0) {
document.getElementById(_target).innerHTML="<b>No Information
Available</b>";
return;
}
xmlHttp = GetAJAXObject();
if (xmlHttp==null) {
alert ("Unable to process your request, your browser does not support
AJAX!");
return;
}
var url = "http://127.0.0.1:80/webapp/php/"+url+";;
xmlHttp.onreadystatechange = showResult;
xmlHttp.open("GET",url,true);
xmlHttp.send(null);
}
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