The engine's efficiency is 10%
So it converts 10% of 250kJ into useful work=25 kJ
W=mgh
25000=1•10•h
h=2500m??????
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-----Original Message-----
From: "LAKKAPPA M PUJAR" <[email protected]>
Sent: 7/20/2016 10:53 AM
To: "[email protected]" <[email protected]>
Subject: [ms-stf '62056'] Plz solve anyone
The efficiency of heat engine is 10.if the heat energy consumed by the engine
is 250KJ how high would this engine lift an object of mass 1Kg from the ground?
(assume that g=10m/s2 remember :w=mgh)
Lakkappa M Pujar
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