On Fri, Sep 18, 2009 at 9:48 AM, Sandro Tosi <matrixh...@gmail.com> wrote:
> Hi all,
> with the simple code here below
>
> $ ipython -pylab
>
> In [1]: import numpy as np
>
> In [2]: theta = np.arange(0., 2., 1./180.)*np.pi
>
> In [3]: plt.polar(3*theta, theta/5)
>
> I obtain the attached images with 0.98.5.3 and 0.99.{0.1rc1} (didn't
> have time to test against SVN).
>
> AFAIUI, the 0.98.5.3 should be the correct behavior, so in 0.99.x
> there's a regression.

I filed a report at
https://sourceforge.net/tracker/?func=browse&group_id=80706&atid=560720.

JDH

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