>>>>> "Glen" == Glen W Mabey <[EMAIL PROTECTED]> writes:
Glen> Hello, I have been unable to discover in the docs a method
Glen> for discovering the exact size in pixels of an axes.
Glen> The only way I have thought of is to get the size of the
Glen> canvas via FigureCanvas.get_width_height() and then multiply
Glen> by the results of axes.get_position(), but really I want to
Glen> have the exact size in pixels.
In [1]: ax = subplot(111)
In [2]: left, bottom, width, height = ax.bbox.get_bounds()
In [3]: print left, bottom, width, height
80.0 48.0 496.0 384.0
However, this question looks like one that would be better answered by
describing what you are trying to do. There may be a more elegant
solution using some of matplotlib's built-in coordinate systems which
would prevent you from having to do raw pixel calculations, which is
not usually what you want. So you may want to describe your actual
problem rather than your solution <wink>
JDH
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