Thanks, this is what I wanted. I overlooked the cumsum() on the end of my array, so the output of the array was not what I expected or needed.
Could you help me figure out how to get an axis label and numbers on the right side of my graph. It is the same data and scale as the left side except it will read Leaf B. On Dec 14, 2007 9:09 PM, Eric Firing <[EMAIL PROTECTED]> wrote: > Bryan Fodness wrote: > > I would also like to get the area of the mesh element when I fill the > > corresponding array element. > > > > if a[1,0] > > area = 1.0 * 0.01 > > > > if a[30,0] > > area = 0.5 * 0.01 > > > > Is this possible? > > I'm sorry, but I don't understand what you are asking. Are you asking > how to calculate an array of areas corresponding to the grid? You know > what the delta-Y values are: > > dy = numpy.array([1.4] + [1.0]*9 + [0.5]*40 + [1]*9 + [1.4]) > > Are you looking for > > area = dy * 0.01 > > ? > > Eric > > > On Nov 26, 2007 7:02 PM, Eric Firing <[EMAIL PROTECTED] > > <mailto:[EMAIL PROTECTED]>> wrote: > > > > Bryan Fodness wrote: > > > Could someone give me an idea how to get started with this so it > > > coincides with my array of values. I took a look at the > > quadmesh_demo > > > in the examples and do not see a straightforward way to do this > > > > Maybe the docstrings make it sound more complicated than it really > is. > > In your case you have an array of rectangles, not general > > quadrilaterals. All you need are two 1-D arrays, one each for the x > > and > > y grid boundaries. Something like this: > > > > Z = numpy.random.rand(60,4000) > > X = numpy.arange(4001) > > Y = numpy.array([0, 1.4] + [1.0]*9 + [0.5]*40 + [1]*9 + [1.4 > ]).cumsum() > > pcolor(X, Y, Z) > > > > pcolormesh should work the same, but when I try it now with svn it > > doesn't; I don't know what is going on with it. If you are using a > > release version of mpl, I expect it will work. > > > > Eric > > > > > > > > On Nov 26, 2007 7:52 AM, Michael Droettboom <[EMAIL PROTECTED] > > <mailto:[EMAIL PROTECTED]>> wrote: > > >> You can provide mesh coordinates to the pcolor command: > > >> > > >> X and Y, if given, specify the (x,y) coordinates of the > colored > > >> quadrilaterals; the quadrilateral for C[i,j] has corners at > > >> (X[i,j],Y[i,j]), (X[i,j+1],Y[i,j+1]), (X[i+1,j],Y[i+1,j]), > > >> (X[i+1,j+1],Y[i+1,j+1]). Ideally the dimensions of X and Y > > >> should be one greater than those of C; if the dimensions are > the > > >> same, then the last row and column of C will be ignored. > > >> > > >> Actually generating the mesh is up to you (wink), but hopefully > that > > >> allows for what you need to do. > > >> > > >> Cheers, > > >> Mike > > >> > > >> > > >> Bryan Fodness wrote: > > >>> I am wondering if there is a way to view my data with respect > > to the > > >>> physical size of what my array element is suppose to be. > > >>> > > >>> I have an array that is 60 x 4000 where, > > >>> the first row has a height of 1.4 > > >>> the next nine has a height of 1 > > >>> the next forty has a height of 0.5 > > >>> the next nine has a height of 1 > > >>> and the last one has a height of 1.4 > > >>> > > >>> When viewing this with contourf or pcolor, the image is more > narrow > > >>> than it should be. Is there an easy way to view this properly. > > >>> > > >>> Bryan > > >>> > > >> -- > > >> Michael Droettboom > > >> Science Software Branch > > >> Operations and Engineering Division > > >> Space Telescope Science Institute > > >> Operated by AURA for NASA > > >> > > > > > > > > > > > > > > > > > > > -- > > "The game of science can accurately be described as a never-ending > > insult to human intelligence." - João Magueijo > > -- "The game of science can accurately be described as a never-ending insult to human intelligence." - João Magueijo
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