Chris,
Why wouldn't you try to use sorted on your dictionary, construct an array from
the result of sorted, and get the corresponding columns ?
>>>ddict={date(2008,01,01):10,date(2008,01,03):20,date(2008,01,02):30}
>>>results=numpy.array(sorted(ddict.iteritems()),)
>>>print results[:,0]
>>>[2008-01-01 2008-01-02 2008-01-03]
>>>print results[:,1]
>>>[10 30 20]
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