On Thu, May 8, 2008 at 3:52 PM, Michael Droettboom <[EMAIL PROTECTED]> wrote:
> You can pass an "interpolation" parameter to imshow, or set a default in
> "image.interpolation" in your matplotlibrc. From the imshow docstring:
>
> * interpolation is one of:
>
> 'nearest', 'bilinear', 'bicubic', 'spline16', 'spline36',
> 'hanning', 'hamming', 'hermite', 'kaiser', 'quadric',
> 'catrom', 'gaussian', 'bessel', 'mitchell', 'sinc',
> 'lanczos', 'blackman'
>
> if interpolation is None, default to rc
> image.interpolation. See also th the filternorm and
> filterrad parameters
>
> 'nearest' is the one you want if you want to see sharp square pixels.
>
Thanks mike, thats exactly what I needed :)
>
> Søren Nielsen wrote:
>
>> Also, if I want to use matplotlib.patches on a canvas where I can actually
>> see individual pixels, is it possible to only draw on the available pixels
>> showing, and not just make a nice high resolution line that is plotted on
>> top of my image?
>>
> I'm not sure I understand the question. You mean to draw a line using
> large pixels, rather than as a vector? I don't think there's an easy way on
> that one -- but maybe someone else here can think of a creative way to do
> it.
Yes you understod it correctly, I guess I could figure out what pixels are
involved in a line or a circle for instance, and then do a scatter plot on
those pixels to form the shape.. but it sounds really computationally
heavy.. and I need something that works fast, (the user should be able to
mask a circle in an image using the pixels available in the image) Also the
circle should be shown as it is created (like choosing a center and moving
the mouse enlarges the circle).
Maybe someone tried this? masking stuff in an image seems like a fairly
common thing :)
Thanks for the help!
Soren
>
> Cheers,
> Mike
>
>>
>> Thanks,
>> Soren
>>
>>
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>
> --
> Michael Droettboom
> Science Software Branch
> Operations and Engineering Division
> Space Telescope Science Institute
> Operated by AURA for NASA
>
>
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