If I do: t1=datetime.datetime(2008,06,02,01,0,0) t1=datetime.datetime(2008,06,02,02,0,0) tVec1=drange(t1,t2,datetime.timedelta(seconds=1)) tVec2=drange(t1,t2,datetime.timedelta(seconds=5)) tVec3=nan*ones(tVec1.shape)
I cannot do something like: for i in tVec2: tVec3[where(tVec1==i)]=i tVec3[0] is written, yet the others are not. print tVec1[0] > 733195.083333 print tVec1 >[ 733195.08333333 733195.08334491 733195.08335648 ..., 733195.50376352 733195.5037751 733195.50378667] There is more precision in the second statement and, I believe, the result for no matches inside the for loop. Is this the desired behavior? I can do: vec1=arange(0,100,1) vec2=arange(0,100,5) vec3=nan*ones(tVec1.shape) for i in vec2: vec3[where(vec1==i)]=i thanks, Brian -- Brian E. McLaughlin Oceanographic Research Specialist Department of Oceanography School of Ocean and Earth Science and Technology University of Hawaii at Manoa Honolulu, HI 96822 -- e:[EMAIL PROTECTED] p:808.956.7625 f:808.956.9516 -- ------------------------------------------------------------------------- This SF.net email is sponsored by: Microsoft Defy all challenges. Microsoft(R) Visual Studio 2008. http://clk.atdmt.com/MRT/go/vse0120000070mrt/direct/01/ _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
