Eric Firing wrote:
> Michael Droettboom wrote:
>> As a quick-fix workaround, you can do:
>>
>> from matplotlib.pyplot import *
>> p = scatter([0,1,2,3], [4,5,6,7], c ='k', alpha=0, edgecolor = 'k')
>> p._alpha = 1.0
>> p.set_edgecolor('k')
>> show()
>>
>> But the deeper question is for the rest of the list is... what's the 
>> correct behavior?  Should we just revert to what it did in 0.91, or add 
>> another kwarg to set the edge alpha?
> 
> I think 0.91 behavior was odd, if alpha applied only to the fill; making 
> alpha apply to everything strikes me as a bugfix, not a regression, so I 
> would not favor reverting to the old behavior.
> 
> What is really needed may be some rethinking (or perhaps just 
> codification) of overall alpha handling throughout mpl, including kwargs 
> and explicit color specification.  At present it seems rather messy, for 
> understandable historical reasons, partly owing to backend quirks and 
> limitations (e.g., no alpha at all in postscript).
> 
> If the kwarg strategy is chosen, then everywhere there can be an edge 
> and a face, we should support "alpha=" to apply to both, "edgealpha=" 
> for the edge alone", and "facealpha=" for the face.  Or something like that.

+1

> Eric
> 
>> Cheers,
>> Mike
>>
>> S Murthy Kambhampaty wrote:
>>> There seems to have been a change to the behavior of the 'alpha' keyword 
>>> option to scatter(): where previously alpha only affected the facecolor, 
>>> and the edgecolor always had an alpha of 1.0, alpha now seems to affect 
>>> both facecolor and edgecolor.  Tested with 0.93.1 and 0.98.  Tested with 
>>> new API for 0.98 as well.
>>>
>>> ax.scatter(xSeries, ySeries, s=sY, c='k', alpha=0, edgecolor='k')
>>>
>>> and 
>>>
>>> plot1=ax.scatter(xSeries, ySeries, s=sY, c='k')
>>> plot1.set_alpha(0)
>>> plot1.set_edgecolor('k')
>>>
>>> Is there any way to get the old behavior using version 0.98 and forward?
>>>
>>> Thanks,
>>>    Murthy
>>>
>>>
>>>
>>>       
>>>
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