Thank you John,
Just what I was looking for.
John Hunter-4 wrote:
>
> On Wed, Jul 30, 2008 at 9:17 AM, stuartornum <[EMAIL PROTECTED]> wrote:
>>
>> Hi,
>>
>> Wondering if anyone has done something similar and could point me in the
>> right direction.
>>
>> I have a dictionary like this:
>>
>> Dict{'00:00:00':'23', '00:01:00':'29', '00:02:00':'13', '00:03:00':'78',
>> '00:04:00':'45', >....> '23:59:00':54}
>>
>> So as you can see there is 24 hours worth of minutes, with a value
>> attached
>> to each minute.
>>
>> Firstly, just to note the Dictionary "Dict" is not actually in order as
>> above, it is all jumbled up.
>>
>> However is it possible to plot a dictionary using MatPlotLib, and using
>> the
>> time along the x-axis and values up the y?
>
> You will have to extract the x and y values, and convert them from
> strings to values matplotlib can understand (for example dates and
> floating point numbers). Eg
>
>
> In [30]: d = {'00:00:00':'23', '00:01:00':'29', '00:02:00':'13',
> '00:03:00':'78',
> '00:04:00':'45', '23:59:00':54}
>
> In [32]: from dateutil.parser import parse
>
> In [33]: items = [(parse(date), float(val)) for date, val in d.items()]
>
> In [34]: items.sort()
>
> In [35]: items
> Out[35]:
> [(datetime.datetime(2008, 7, 30, 0, 0), 23.0),
> (datetime.datetime(2008, 7, 30, 0, 1), 29.0),
> (datetime.datetime(2008, 7, 30, 0, 2), 13.0),
> (datetime.datetime(2008, 7, 30, 0, 3), 78.0),
> (datetime.datetime(2008, 7, 30, 0, 4), 45.0),
> (datetime.datetime(2008, 7, 30, 23, 59), 54.0)]
>
> In [36]: dates, values = zip(*items)
>
> In [37]: plot(dates, values)
> Out[37]: [<matplotlib.lines.Line2D object at 0xb45a5ec>]
>
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