lionel keene wrote: > Hello all, I'd like to create a "matplotlib.pyplot.figure(...)" object > and specify the size while I'm at it. I see this argument list from > the matplotlib's documentation: > > pyplot.figure(num=None, figsize=(8, 6), dpi=80, facecolor='w', edgecolor='k') > > The on-screen size is being computed using inches (for height and > width) and dpi. But I don't know what the dpi is in advance. What can > I do? In case it's relevant, I'm using Python 2.5 and the latest > download of matplotlib. > > Thanks in advance. > > -L
I'm not quite sure I understand; if you don't know the dpi when you create the figure, when *will* you know it? Lack of knowledge of the actual dpi of a display is a general problem, and I don't know of any general solution. Typically one has to guess, or let the user measure it and input it as a variable at the start of a graphics program. Ideally, every display would communicate its dpi to the operating system, and graphics software would be able to read and use this value. I don't know if any systems actually work this way. Eric ------------------------------------------------------------------------------ Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
