Michael Hearne wrote:
> Is it possible to use multiple conditionals with the pylab.find() function?
> 
> For example, in Matlab, I can do the following:
> 
> x = rand(1,10);
> i = find(x > 0.5 & x < 0.9); %returns the indices between 0.5 and 0.9
> 
> In Python: (ipython -pylab)
> x = rand(1,10)
> 
> None of the following approaches work:
> #i = find(x > 0.5 and x < 0.9)
> #i = find(x > 0.5 && x < 0.9)
> #i = find(x > 0.5 & x < 0.9)
> 
> I'm pretty certain there is some other way to do this using a numpy 
> method, and if that's all there is, then I will happily use it.
> 
> However, if the goal of the pylab module is to achieve (some level of) 
> compatibility with Matlab, then may I suggest this sort of functionality 
> be added to the pylab.find() function?

This is a fundamental python/numpy problem.  The workaround is

x = rand(10)
i = find((x > 0.5) & (x < 0.9))

Note the explicit parentheses to make the conditionals evaluated before 
the bitwise and.  The real problem is that we are stuck using bitwise 
and as a surrogate for logical and. This problem is not going away any 
time soon, although proposed solutions have been discussed.

Also note that in numpy we are using a 1-D array.  If you really want 
the 2-D array, then you will have to index it as x[:,i].

Longer term, the recommendation is that you move away from trying to 
write matlab code using pylab, and instead use numpy idioms directly.

import numpy as np
x = np.random.rand(10)
y = x[(x > 0.5) & (x < 0.9)]

or if you really want the indices:

i = np.nonzero((x > 0.5) & (x < 0.9))[0]



Eric

> 
> Thanks,
> 
> Mike
> 
> 
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