Hi Andrew, if I understand correctly "set_clip_path" is what you want. The usage was discussed in the following threads, where John Hunter also proposed the example code added below.
http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg10155.html http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg08779.html The only example I found on the web and in the svn-examples about clip_path is http://matplotlib.sourceforge.net/examples/pylab_examples/image_clip_path.html?highlight=clip_path For developers: Could it be useful to include John's example in the online screenshots / gallery or did I miss it? best regards Matthias """ Clipping to arbitrary patches and paths """ import numpy as np import matplotlib.pyplot as plt import matplotlib.path as path import matplotlib.patches as patches fig = plt.figure() ax = fig.add_subplot(111, frameon=False, xticks=[], yticks=[]) im = ax.imshow(np.random.rand(10,10)) patch = patches.Circle((300,300), radius=100) im.set_clip_path(patch) plt.show() On Wednesday 15 April 2009 09:01:56 Andrew Kelly wrote: > Hello,I am relatively new to matplotlib but I get the basics. What I need > to do though is a slightly customized graph area. There are two plots on > the same graph - a parabola and a straight line (with a negative slope) > north east of the parabola. This graph has grid lines. Simple enough, but > now I want to remove the graph area to the right of the line. Think of a > dog-eared page in a book. Basically that top right triangle is gone. > > Can I do this in MPL or do I need to do some post processing in PIL? Much > thanks for any help. > > -Andrew
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