Hi Jae-Joon,
Thanks for the quick fix! Just looked in the svn browser, and noticed
you changed line 5290 of axes.py to
'o' : (0,0,3),
Should this not be
'o' : (0,3,0),
?
Thanks,
Tom
On Jun 21, 2009, at 2:59 PM, Jae-Joon Lee wrote:
> Thanks for the report.
> And, this turned out to be a bug. The symbol style code was simply
> ignored when its value is 3.
>
> While the bug should now be fixed (both in the trunk and the maint.
> branch), you may use marker style like (20,0,0) (or increase the first
> number when symbol is large) for a workaround.
>
> Regards,
>
> -JJ
>
>
> On Sun, Jun 21, 2009 at 1:09 PM, Thomas
> Robitaille<thomas.robitai...@gmail.com> wrote:
>>
>> Hi,
>>
>> I'm trying to use the scatter method, making use of the option to
>> specify
>> the marker as a tuple. From the documentation, it would seem that
>> specifying
>> marker=(0,3,0) should draw a circle. However, this is not the case.
>> If you
>> consider the following code:
>>
>> import matplotlib
>> matplotlib.use('Agg')
>> import matplotlib.pyplot as mpl
>>
>> fig = mpl.figure()
>> ax = fig.add_subplot(111)
>> #ax.scatter([x],[y],c='red',marker=(0,3,0.))
>> ax.scatter([10.],[10.],c='red',marker=(3,3,0.))
>> ax.scatter([11.],[10.],c='red',marker=(6,3,0.))
>> ax.set_xlim(5.,15.)
>> fig.savefig('scatter.png')
>>
>> The first ax.scatter causes an error, the second plots a triangle,
>> and the
>> third a hexagon. However, the documentation states that (a) setting
>> the
>> second element to '3' should plot a circle, and (b) the other
>> arguments
>> should be ignored, so the first ax.scatter should not cause an error.
>>
>> Is this a bug, or am I misunderstanding the documentation?
>>
>> Thanks,
>>
>> Thomas
>> --
>> View this message in context:
>> http://www.nabble.com/possible-bug-with-scatter-tp24136534p24136534.html
>> Sent from the matplotlib - users mailing list archive at Nabble.com.
>>
>>
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