Ah, I was a little confused by what you wrote John (I though I had to access contour through the axes object and the meaning of R, F, dR was a little unclear..) however using the 'levels' keyword now works. i.e.
plt.contour(x, y, z, levels=[0]) Incidentally, this keyword (levels) is not documented at http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.contour and in fact the documentation implies that contour(kx, ky, z, [0]) should work when it does not. Perhaps the docs could be updated to reflect this? Brendan On Tue, Nov 3, 2009 at 2:19 PM, Brendan Arnold <brendanarn...@gmail.com> wrote: > Hi again, > > Thanks for the responses, however neither work, the error still > persists. Here are more details... > > Traceback (most recent call last): > File "C:\Program Files\Python\2.5\lib\lib-tk\Tkinter.py", line 1403, > in __call__ > return self.func(*args) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\backends\backend_tkagg.py", > line 212, in resize > self.show() > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\backends\backend_tkagg.py", > line 215, in draw > FigureCanvasAgg.draw(self) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\backends\backend_agg.py", > line 314, in draw > self.figure.draw(self.renderer) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\artist.py", line 46, in > draw_wrapper > draw(artist, renderer, *kl) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\figure.py", line 773, in > draw > for a in self.axes: a.draw(renderer) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\artist.py", line 46, in > draw_wrapper > draw(artist, renderer, *kl) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\axes.py", line 1735, in > draw > a.draw(renderer) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\text.py", line 515, in > draw > bbox, info = self._get_layout(renderer) > File "C:\Program > Files\Python\2.5\lib\site-packages\matplotlib\text.py", line 257, in > _get_layout > if key in self.cached: return self.cached[key] > TypeError: unhashable type: 'numpy.ndarray' > >>>> matplotlib.__version__ > '0.99.1' >>>> numpy.__version__ > '1.3.0' > > Python version 2.5 > > the code in full is as follows, > > import matplotlib > import numpy as np > import matplotlib.cm as cm > import matplotlib.mlab as mlab > import matplotlib.pyplot as plt > > # Set some model parameters > model_points = 10000 > t0 = 0.38 > t1 = 0.32*t0 > t2 = 0.5*t1 > > def energy(kx, ky): > '''Energy function, evetually this will be provided by raw data > from WIEN2k''' > return -2*t0*(np.cos(kx)+np.cos(ky)) \ > + 4*t1*np.cos(kx)*np.cos(ky) \ > - 2*t2*(np.cos(2*kx)+np.cos(2*ky)) > > def shift_energy_up(energy_val, dE): > '''Shifts the energy according to a gap''' > return energy_val + np.sqrt(energy_val**2 + dE**2) > > def shift_energy_dn(energy_val, dE): > '''Shifts the energy down according to an energy''' > return energy_val - np.sqrt(energy_val**2 + dE**2) > > kx = np.arange(0, 2*np.pi, 2*np.pi/np.sqrt(model_points)) > ky = np.arange(0, 2*np.pi, 2*np.pi/np.sqrt(model_points)) > mgx, mgy = np.meshgrid(kx, ky) > z = energy(mgx, mgy) > > # Set the ticks to go outwards > matplotlib.rcParams['xtick.direction'] = 'out' > matplotlib.rcParams['ytick.direction'] = 'out' > > plt.figure() > CS = plt.contour(kx, ky, z, [0, 0]) > plt.clabel(CS, inline=1, fontsize=10) > plt.title('Simplest default with labels') > plt.show() > > > kind regards, > > Brendan > > On Mon, Nov 2, 2009 at 9:33 PM, Pierre de Buyl <pdeb...@ulb.ac.be> wrote: >> From memory, you just need to make a length one list >> >> contour(z, [i]) >> >> Pierre >> >> Le 2 nov. 09 à 22:19, Brendan Arnold a écrit : >> >>> Hi there, >>> >>> I can draw a single contour line in MATLAB using >>> >>> contour(z, [i i]) >>> >>> however, >>> >>> contour(z, [i, i]) >>> >>> using matplotlib gives an error. In fact any plot that plots a single >>> line (i.e. contour(z, 1)) also gives an error as follows, >>> >>> TypeError: unhashable type: 'numpy.ndarray' >>> >>> How do I draw a single contour line using matplotlib? >>> >>> regards, >>> >>> Brendan >>> >>> >>> ------------------------------------------------------------------------------ >>> Come build with us! The BlackBerry(R) Developer Conference in SF, CA >>> is the only developer event you need to attend this year. Jumpstart your >>> developing skills, take BlackBerry mobile applications to market and stay >>> ahead of the curve. Join us from November 9 - 12, 2009. Register now! >>> http://p.sf.net/sfu/devconference >>> _______________________________________________ >>> Matplotlib-users mailing list >>> Matplotlib-users@lists.sourceforge.net >>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> >> > ------------------------------------------------------------------------------ Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day trial. Simplify your report design, integration and deployment - and focus on what you do best, core application coding. Discover what's new with Crystal Reports now. http://p.sf.net/sfu/bobj-july _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
