...although

 >>plot(map(lambda x:x**2, range(5,15)))

probably doesn't do exactly what you want; is the idea that

 >>plot(range(5,15),lambda x:x**2) #DOESN'T WORK

should automatically work like

 >>plot(range(5,15), map(lambda x:x**2, range(5,15)))

by recognizing that the second argument is a function rather than a  
list?

&C


On Mar 10, 2010, at 10:47 AM, Chloe Lewis wrote:

> You'd always have to specify the domain, so
>
> plot(map(lambda x:x**2, range(1,10)))
>
> shouldn't be much longer than the minimal command.
>
> &C
>
>
> On Mar 10, 2010, at 10:12 AM, max ulidtko wrote:
>
>> Hi.
>>
>> Is it possible to plot arbitrary lambda function with matplotlib?
>> Say, if i have f = lambda x: x*sin(x), can i just plot it without
>> building argument-value arrays? It would be a very convenient and
>> useful feature.
>>
>>
>> ------
>> Sincerely,
>> max ulidtko
>> ------------------------------------------------------------------------------
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>
>
> ------------------------------------------------------------------------------
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> Try the new software tools for yourself. Speed compiling, find bugs
> proactively, and fine-tune applications for parallel performance.
> See why Intel Parallel Studio got high marks during beta.
> http://p.sf.net/sfu/intel-sw-dev
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