Ryan ...,
Very good ..., it works perfectly ...
It's so easy but I didn't remember to use it ...
In fact my problem is slightly more complicated than this because I have
used textName[ 2 ] instead of literal LotoFácil as I told you ( I
know I didn't say this before, my fault ), the correct code is ...
fig.suptitle( textName[ 2 ], fontsize = self.fon[ 6 ][ 1 ], fontweight =
"extra bold",
fontstyle = "italic", color = self.cor[ 608 ][ 1
], lod = True )
however, after your mention about /unicode string/ you gave me a good
idea so I solved my problem this way ...
fig.suptitle( unicode( self.textName[ 2 ], "cp1252" ), fontsize =
self.fon[ 6 ][ 1 ], fontweight = "extra bold",
fontstyle = "italic", color = self.cor[ 608 ][ 1
], lod = True )
and everything works perfectly again.
But I was thinking that the correct way is to fix it there in cbook.py,
anyway ...
File "C:\Python26\lib\site-packages\matplotlib\cbook.py", line 1682, in
is_math_text
s = unicode(s)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe1 in position 5:
ordinal not in range(128)
Thank you very much for your prompt aid,
Ademir Francisco da Silva
Em 03/07/2010 19:05, Ryan May escreveu:
On Sat, Jul 3, 2010 at 4:12 PM, Ademir Francisco da Silva
<ademirfs_...@itelefonica.com.br> wrote:
excerpt of may code is ...
fig.suptitle( "LotoFácil", fontsize = self.fon[ 6 ][ 1 ], fontweight = "extra
bold",
fontstyle = "italic", color = self.cor[ 608 ][ 1 ], lod
= True )
but I'm Brazilian and this is not correct for us. Help me please.
Try using a python unicode string instead:
fig.suptitle( u"LotoFácil", fontsize = self.fon[ 6 ][ 1 ], fontweight
= "extra bold",
fontstyle = "italic", color = self.cor[ 608 ][
1 ], lod = True )
That works for me here (though with the original, I just get missing
characters, not an error).
Ryan
--
Ademir Francisco da Silva
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