On 08/01/2010 07:35 AM, Benjamin Root wrote:
> On Sun, Aug 1, 2010 at 9:55 AM, Tom Arens <tak...@gmx.de
> <mailto:tak...@gmx.de>> wrote:
>
>     Hello everyone,
>
>     does anybody know why the contour3D function has a fixed set of levels?
>
>     contour3D(X, Y, Z, levels=10, **kwargs)
>
>     I want to plot only one line for one level. With "contourf" it works:
>
>
>
>     from mpl_toolkits.mplot3d import axes3d
>     import matplotlib.pyplot as plt
>
>     fig = plt.figure()
>     ax = axes3d.Axes3D(fig)
>     X, Y, Z = axes3d.get_test_data(0.05)
>     cset = ax.contourf(X, Y, Z, 0)  # doesn't work with contour
>     ax.clabel(cset, fontsize=9, inline=1)
>
>     plt.show()
>
>
>
>     Many greetings,
>     Tom
>
>
> Hmm, interesting.  Looking at the contour3d call signature, it appears
> that 'levels' was put into the call signature to basically remove that
> keyword argument from the kwargs that get passed down to the 2-d version
> of contour.  It is never used in the body of contour3d().
>
> I would guess that this is might be a remnant of some original code that
> actually used the levels parameter.  Simply removing levels=0 from the
> call signature seems to fix it (and passing [0] to levels as well since
> it expects a sequence).
>
> As a matter of consistency, I think the call signature should be changed
> to better match the call signature for contourf3d() and for the 2-d
> version of contour().

Ben,

Good idea, go ahead.  The contourf3d docstring can also be modified to 
match your change to the contour3d docstring.

I would consider all this as bug-fixing, so it can go in branch and trunk.

Thanks.

Eric

>
> Ben Root
>

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