I realized after sending that off that I need to provide more
context....sorry about that.
What I'm trying to do can be boiled down to the following: I'm trying to
place a legend precisely, using the top left corner of legend as the
"sticky" point. In other words, if I want to place the legend here:
+---------------------------------+-----------+
| | |
| | legend |
| The plot... |-----------+
| |
| |
| |
| |
| |
| |
+---------------------------------+
I would have thought that I would set bbox_to_anchor = (0,0,1,1), and loc =
(1,1). I found out quickly, though, that this places the legend like this:
+-----------+
| |
| legend |
+---------------------------------+-----------+
| |
| |
| The plot... |
| |
| |
| |
| |
| |
| |
+---------------------------------+
Which makes perfect sense from matplotlib's perspective. So all I need to
do is figure out how tall the legend is, and subtract that off the y
coordinate before passing 'loc' off to matplotlib's legend. I just can't
seem to figure out how to get that number. I tried
self.ax.get_legend().get_frame().get_height(), but that just returns 1 all
the time.
Ascii art is fun! :)
--
Daniel Hyams
dhy...@gmail.com
------------------------------------------------------------------------------
Nokia and AT&T present the 2010 Calling All Innovators-North America contest
Create new apps & games for the Nokia N8 for consumers in U.S. and Canada
$10 million total in prizes - $4M cash, 500 devices, nearly $6M in marketing
Develop with Nokia Qt SDK, Web Runtime, or Java and Publish to Ovi Store
http://p.sf.net/sfu/nokia-dev2dev
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