On Thu, Jan 6, 2011 at 12:57 AM, Sebastian Voigt <svo...@gmx.de> wrote:
> Am 06.01.2011 02:14, schrieb Benjamin Root:
>
> On Wed, Jan 5, 2011 at 6:15 PM, Sebastian Voigt <svo...@gmx.de> wrote:
>
>> I've been running into the well known rendering problems with mplot3d's
>> bar3d function. After two days of trying to get acceptable results
>> without success: Is it possible to simply disable z-sorting (whoops)?
>>
>> I want to generate static plots from experimental data, all using the
>> same perspective, so I know the order of the bars to be plotted. It's a
>> no-brainer to provide the data vectors in this appropriate order, which
>> I tried too - didn't work. Even if I provide explicit zorders for all
>> Poly3dCollections in axes.collections (single-plotting each bar),
>> everything gets messed up after showing the plot window.
>>
>> So is there any way to create the bars just in the order of the data
>> vectors passed to bar3d (or keep the order/zorder in axes.collections)?
>>
>>
>> - Sebastian Voigt -
>>
>>
> There are well-known rendering issues with mplot3d in general, but I am not
> aware of one with respect to bar3d. Can you please include a image of the
> rendering defect that you are seeing?
>
> And no, there is no way to disable z-sorting that I am aware of because it
> is inherent in matplotlib's system. mplot3d merely utilizes the drawing
> facilities that matplotlib provides.
>
> Ben Root
>
>
> It's exactly the same problem as described in
>
>
> http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg15243.html
>
> see the second sample pic in this post. If I cannot disable z-sorting, how
> can I control it? Artist have a set_zorder() method, but providing correct
> z-levels for all my artists seems to be ignored.
>
> Sebastian
>
Sebastian, looking at those images, I have to wonder if there is a bug in
how bar3d is reporting the z-order. These rendering mistakes do not seem to
follow the same patterns that I have seen with manually setting polygon
objects. I will take a deeper look into it.
Ben Root
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