On Fri, Feb 25, 2011 at 5:34 PM, Philipp A. <flying-sh...@web.de> wrote:
> 2011/2/25 Philipp A. <flying-sh...@web.de> > > 2011/2/25 Benjamin Root <ben.r...@ou.edu> >> >>> On Fri, Feb 25, 2011 at 8:09 AM, Philipp A. <flying-sh...@web.de> wrote: >>> >>>> hi, >>>> Axes3D from mpl_toolkits.mplot3d does not override set_*ticklabels. >>>> this >>>> bug<http://sourceforge.net/tracker/index.php?func=detail&aid=2874110&group_id=80706&atid=560720>is >>>> about the issue. >>>> to get a crude replacement, i have to do the following: >>>> >>>> for x, s in enumerate(ticks): >>>>> ax.text3D(x, -.1, -.5, s) >>>>> for a in ax.w_xaxis.get_ticklabels(): >>>>> a.set_visible(False) >>>>> >>>> >>>> is there a way to do better and hack my values into the real tick >>>> labels (i bet they are drawn internally the same as text3D, but there is no >>>> way to access the values)? >>>> >>>> >>> In matplotlib in the development branch, I am able to call >>> ax.w_xaxis.set_ticklabels() (or ax.w_yaxis, or ax.w_zaxis) and have the >>> ticks show up appropriately. I have not tested earlier versions of >>> matplotlib, though. Which version are you using? >>> >>> Admittedly, the control of the ticks is very poor in mplot3d. I hope to >>> improve that over the next several months. >>> >>> Ben Root >>> >> >> i use 0.99.3 both in university and at home, but somehow at home, >> matplotlib complains about ValueError: Unknown projection '3d' at home. >> >> i’ll try 1.0.1 and report if it works. >> > > update: i’ll see if a dev build does the trick tomorrow, as a local build > of 1.0.1 doesn’t show the x/yticklabels and there doesn’t exist a function > named set_zticklabels. > Phillipp, The ability to call ax = fig.gca(projection='3d') was new for version 1.0.0. This morning, I also noticed that functions like "set_zticklabels()" did not exist. I currently have a patch submitted for that and it should be merged into the git repository tonight. In the meantime, you can always do something like: ax.w_zaxis.set_ticklabels() The functions like ax.set_zticks() merely call that function for the appropriate axis. Ben Root
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