On Tue, May 31, 2011 at 12:58 PM, Eric Firing <efir...@hawaii.edu> wrote:
> On 05/31/2011 05:50 AM, Benjamin Root wrote:
> >
> >
> > On Tue, May 31, 2011 at 10:34 AM, Mannucci, Anthony J (335G)
> > <anthony.j.mannu...@jpl.nasa.gov
> > <mailto:anthony.j.mannu...@jpl.nasa.gov>> wrote:
> >
> > The following program seems to work with contour/contourf. However
> > the documentation for the contourf function states
> >
> > contour(X,Y,Z)
> >
> > "/X/, /Y/, and /Z/ must be arrays with the same dimensions."
> >
> > I am finding that contour works if the dimension of X and Y are 1,
> > but Z must be two-dimensional. The following program seems to bear
> > this out. Are the arrays x and y below two-dimensional, or is the
> > documentation misleading? Thanks for your help.
> >
> > import numpy as N
> > import pylab as PLT
> >
> > lons = N.linspace(-5.,5.,5) # Is this a one or two dimensional array?
> > lats = N.linspace(-3.,3.,4)
> >
> > z = N.zeros((len(lats), len(lons)))
> > for i in range(len(lons)):
> > for j in range(len(lats)):
> > z[j,i]=i+j
> >
> > PLT.clf()
> > PLT.contourf(lons,lats,z)
> > PLT.colorbar()
> > PLT.show()
> >
> > -Tony
> >
> >
> > Tony,
> >
> > contour and contourf seems to take advantage of numpy's broadcasting
> > feature, so it is probably more correct to say that X and Y must be at
> > least broadcastable to the shape of Z. I think there are a number of
>
> Not quite; if x and y are 1-D, meshgrid is called to make 2-D versions,
> which must then match Z. Broadcasting is not used or supported. So, the
> contour docstring was not updated when this functionality was added,
> long ago. Consider it an undocumented feature, in need of documentation.
>
> Eric
>
>
Well, (as a bit of a cop-out) in my edit, I didn't say that they were
broadcasted, only that they must be broadcastable to the same shape. Would
that suffice, or should I re-word that?
Ben Root
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