Hi,

   there is only one column. so I want a plot of y and x. With y taking
values running from 0 to n  or 7 in my example and x as the average of the
values that are contained in the rows in my example it was 5.57.



mdekauwe wrote:
> 
> still don't quite get this, so you want for each column the average? and
> you want to plot each of these averages? So a bar graph? with 8 bars?
> 
> 
> 
> surfcast23 wrote:
>> 
>> Hi,
>> 
>>    I apologize if my explanation was less than clear. What I have is data
>> in a column that runs from row 1 to row 1268. In each each row there is a
>> number. For example
>> 
>> 1
>> 3
>> 5
>> 6
>> 7
>> 8
>> 9
>> 
>> so I want  the y axis to run from 1 to 7 ( the number of rows) and the x
>> axis to be the average of the values in this case 5.57. I am having
>> problems with setting up the y-axis as well as the dimension   problem
>> you addressed. 
>> 
>>  Is there a way I could have every value on the x axis the same? Say for
>> the above example have the x and y axis  be
>> 
>> 7
>> 6
>> 5
>> 4
>> 3
>> 2
>> 1 
>>   5.75 5.57 5.57 5.75 5.57 5.57 5.75
>> 
>>  Which would be the number of rows vs the average value of the data in
>> the rows and then plot that?
>> 
>> Thanks again
>> 
>> Khary
>> 
>> 
>> 
>> mdekauwe wrote:
>>> 
>>> Hi,
>>> 
>>> Well the first bit about wanting a specific column and the last bit
>>> about not wanting to print all the data in and read it back, you get
>>> that from the example I gave you. If you paste what I wrote for you line
>>> by line it should become clearer for you, additionally it avoids you
>>> have to write your own parsing code.
>>> 
>>> As far as your plotting goes, unless you actually post what you are
>>> entering in the script (exactly as you have it), then it is impossible
>>> to say. For example
>>> 
>>> plt.plot()
>>> plt.show
>>> 
>>> there is no way that is all you have? if it is, then of course you will
>>> get a fail as you are asking matplotlib to plot but are not providing it
>>> with any data to plot!
>>> 
>>> Perhaps I am being particularly dense but "What I now need to do is have
>>> the information in that column plotted as the number of rows vs. the
>>> mean value of all of the rows." means nothing to me. Sorry. What do you
>>> want on the X and Y... do you mean you want to plot your individual
>>> column (8 i think you called it) against the mean of all the other rows?
>>> If so I would expect you would have a dimensions issue
>>> 
>>> Martin
>>> 
>>> 
>>> 
>> 
>> 
> 
> 

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