Brad,
Matplotlib axes objects have set_xticklabels methods. It's brute
force, but this will work:
ax = gca()
ax.set_xticks([0., 0.015, 0.03])
ax.set_xticklabels(['0', '0.015', '0.03'])
Hope that helps,
-paul
On Thu, Mar 29, 2012 at 1:13 PM, Brad Malone <brad.mal...@gmail.com> wrote:
> Hello,
>
> I am working on a plot in which I need to modify the value of the xticks. A
> snippet of my code is attached below:
>
>> fig=figure()
>>
>> gs=matplotlib.gridspec.GridSpec(1,2,width_ratios=[3,1])
>> gs.update(wspace=0.1)
>> ax=subplot(gs[0])
>> ylabel('Frequency (cm'+r'$^{-1}$'+')')
>> for i in range(0,len(ydata)):
>> plot(xdata[i],ydata[i],'r-',linewidth=1.5)
>> plot(xdata[0],[0.0]*len(xdata[0]),'k:')
>>
>> pos=[0,49.9856985699,99.9713971397,170.661849982,212.979781775,283.67023461\
>> 7,333.655933187,375.97386498]
>>
>> locs,labels=xticks(pos,[r'$\Gamma$','X','M',r'$\Gamma$','Z','A','R','X'])
>> for i in range(0,len(pos)):
>> plt.axvline(x=pos[i],linewidth=0.5,color='k',alpha=0.5)
>> axis([0,375.98,0,300])
>> ax2=subplot(gs[1])
>> plot(dosydata,dosxdata,'r-',linewidth=1.5)
>> a=gca()
>> b=a.get_xticks()
>> print b
>> a.xaxis.set_ticks([0.0, 0.015, 0.03])
>> a.tick_params(axis='x',labelsize=14)
>> a.set_xlim([0,0.03])
>> a.set_ylim([0,300])
>> ax.label_outer()
>> ax2.label_outer()
>> show()
>
>
> It's a plot with two subplots. Anyway, the issue I'm running into concerns
> the x-axis on the second subplot. As you can see I have set it explicitly
> with "a.xaxis.set_ticks([0.0, 0.015, 0.03])". However, when I do this it
> shows up as (0.000, 0.015,0.030) which I would really like it to look like
> (0,0.015,0.03). In other words, I don't want extra zeros because they are
> unnecessary and make the text run into my other subplot. So I need to be
> able to format them somehow. How would I achieve this selective formatting
> (because of course I want 0.015 to show up that way and not 0.01).
>
> Thanks so much in advance for the help!
>
> Best,
> Brad
>
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