I have done something slightly different that works more generally. I am
trying to recall it from memory, so some details may be wrong.

Essentially, do the interpolation you want on a filled version of the
masked array (filling with a value that makes sense for your data). Then,
do the same interpolation on the mask, and cast the mask back as booleans.
Finally, build the output masked array by combining the two together with
one of the constructors.

Cheers!
Ben Root
On Jun 26, 2013 7:22 AM, "Jeff Whitaker" <jeffrey.s.whita...@noaa.gov>
wrote:

>   Goodman, Alexander (398J-Affiliate) <alexander.good...@jpl.nasa.gov>
>  June 24, 2013 6:27 PM
> Hi Jeff,
>
> Thanks for the quick reply. However I am a little lost with your suggested
> solution. The issue here is that if datain is a masked array, dataout will
> not be a masked array when order=3 is used unless masked=True is set, but
> this just results in none of the elements (besides those outside the domain
> of xin and yin) being masked. So are you saying to try setting the mask to
> what it would be after running interp() with order=0? I would appreciate a
> more concrete example.
>
> Thanks,
> Alex
>
>
> Alex:  After pondering this a bit more, I don't think you can use order=3
> with masked arrays.  Any reason why you can't using a combo of bilinear and
> nearest neighbor as I described in my previous email?
>
> -Jeff
>
>
>
>
>   Goodman, Alexander (398J-Affiliate) <alexander.good...@jpl.nasa.gov>
>  June 24, 2013 4:30 PM
> Just something I thought I should add to this, but would the following
> code seem like a reasonable workaround? Basically, since map_coordinates()
> cannot handle mask arrays, I thought that perhaps passing in the actual
> mask itself to interp() with order=3 may produce close to reasonable
> results, eg:
>
> dataout = interp(datain, xin, yin, xout, yout, masked=True, order=3)
> maskin = datain.mask.astype(int)
> maskout = interp(datain.mask, xin, yin, xout, yout, order=3)
> dataout.mask = dataout.mask | maskout
>
> Thanks,
> Alex
>
>
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