@Eric: thanks, i see the point
@Jody: thanks for the trick, I'll first try Eric's approach
2013/7/18 Eric Firing <efir...@hawaii.edu>:
> On 2013/07/17 11:25 PM, Gregorio Bastardo wrote:
>> Thanks Mike, it's hard to spot, but still better than nothing. Anyway,
>> could it be the default behaviour of plotting masked arrays (single
>> pixel for an isolated element)?
>
> Gregorio,
>
> I don't think this would be a good idea. It adds quite a bit of
> complexity for a special case--and inevitably, the next request from
> someone would be to have the option of using any marker for the isolated
> points. The concept of "single pixel" gets slippery across backends and
> output devices.
>
> A better solution would be a simple function to identify such isolated
> points, for use when needed, to plot such points however you choose,
> typically with a separate call to "plot" specifying a marker. This way,
> the extra complexity is called explicitly when needed, not carried along
> by every call to "plot".
>
> Eric
>
>>
>> 2013/7/17 Michael Droettboom <md...@stsci.edu>:
>>> You could use a single pixel for a marker (','), I guess. But as you
>>> say, you need at least two points for a line segment.
>>>
>>> Mike
>>>
>>> On 07/17/2013 10:45 AM, Gregorio Bastardo wrote:
>>>> Hi,
>>>>
>>>> The following example demonstrates the problem, value 5 could not be
>>>> seen w/o marker:
>>>>
>>>> data = np.arange(10)
>>>> mask = [0,0,0,1,1,0,1,0,0,0]
>>>> x = np.ma.masked_array(data, mask)
>>>> plot(x)
>>>> plot(x, '+')
>>>>
>>>> In my datasets, isolated unmasked values are rare, but placing a
>>>> marker to spot them makes the whole graph cluttered. I do realize that
>>>> at least 2 valid points are needed for a line segment, but still, is
>>>> there any way to visualize these isolated unmasked values w/o a
>>>> marker?
>>>>
>>>> Thanks,
>>>> Gregorio
>
>
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