The units for Bs are the MVAr injected at a voltage of 1 p.u. As you can see from the derivation below, this is the same as the susceptance in p.u. multiplied by the system base MVA.
S = P - j Qinj = V * conj(Is) = V * conj(Ys*V) = abs(V)^2 * conj(Ys) = abs(V)^2 * (Gs - jBs) Qinj = abs(V)^2 * Bs So as you can see, Bs in p.u. would be numerically equal to Qinj in p.u. at a voltage of 1 p.u. Hope this helps, -- Ray Zimmerman Senior Research Associate 419A Warren Hall, Cornell University, Ithaca, NY 14853 phone: (607) 255-9645 On Apr 9, 2012, at 1:57 PM, iman wrote: > Dear all, > > > > I want to define my case in MATPOWER. From attachment, I have Shunt > Resistance as 10000 and Shunt Reactance equal to -200.So my Z= 10000-200J and > Y=1/10004+J 1/500200 based on the following formula: > > Y=G+JB , G=R/R^2+X^2 and B= -X/R^2+X^2 > > > > > Y=1/10004+J 1/500200 > > > As u see the number for G and B are too small.But if u look at the case 14 in > row 9 column 6 in mpc.bus (Bs, shunt susceptance) is equal to 19. > > So why my data doesn’t make sense? > > Is 19 in P.U? > > Thanks > > > > -- > Best regards > Iman > > <86.xlsx>
