1. Yes. It is taken from the RATE_A column of the branch matrix. 2. Ff gives the flow (apparent power, real power, or current, depending on the option selected) in p.u. at the from end of all branches as a function of a set of voltages and angles (which may or may not correspond to a power flow solution). At the solution, in the case where Ff = Pf, then Ff = results.branch(:, PF)/results.baseMVA. I don't think your rewriting of (5.7) and (5.8) is quite equivalent since both Ff and Ft must be bounded by -Fmax and Fmax, and either can be positive or negative, so Fft has to be the max of the absolute values.
-- Ray Zimmerman Senior Research Associate B30 Warren Hall, Cornell University, Ithaca, NY 14853 phone: (607) 255-9645 On Aug 1, 2013, at 7:48 AM, Sashireka Appalasamy <[email protected]> wrote: > Dear Dr. Zimmerman, > > Just to let you know that I have a number of queries on equation 5.7 and 5.8, > page 29 off the MATPOWER manual as given below, > > 1. Is the Fmax value the same for both the equations? > 2. What is the value for Ff(theta,Vm)? Is it the same as results.branch(X,PF) > for a given executed power flow and Ft(theta,Vm)=results.branch(X,PT) OR > could equation 5.7 and 5.8 be written in the form -Fmax< Fft<Fmax which > also means that equation 5.7 and 5.8 are only considered one at a time and > that Fft value be equivalent to the max of (PF,PT)? > > Thank you in advance for your valuable time > > Sincerely, > Sashi
