You can calculate the symmetrical components (direct, inverse and zero) and if your three-phase network is balanced, you can represent it with a 1-ph equivalent using the direct sequence.
However, distribution networks are in principle unbalanced (unbalanced lines, non-symmetric loads etc.) Regards, Stela Sarri On 05 May 2016, at 13:29, Fiaz Ahmad <[email protected]> wrote: > Yes I m using balanced three phase but how can I do it with matpower. I > changed the bus data and gen.data matrices but I couldn't get the power flows. > > On May 5, 2016 2:24 PM, "Jovan Ilic" <[email protected]> wrote: > > You could use Matpower to simulate distribution systems if you are only > interested in balanced 3 phase without mutual line coupling systems. > > Jovan > > > On Thu, May 5, 2016 at 3:41 AM, Ji Chen <[email protected]> wrote: > Hi Shri, > I am interested in power flows for distribution networks recently. Do you > mean that Matpower is not a good chioce for distribution networks simulation > or it just can not do distribution networks simulation? > > Thanks, > Ji > > > > At 2016-05-04 23:02:50, "Abhyankar, Shrirang G." <[email protected]> wrote: > http://ewh.ieee.org/soc/pes/dsacom/testfeeders/index.html > > However, as Jovan mentioned, MATPOWER is for solving balanced three-phase > transmission systems. If you are interested in solving unbalanced three-phase > power flows for distribution networks then refer to either OpenDSS or > GridLAB-D. > > Shri > > From: Fiaz Ahmad <[email protected]> > Reply-To: MATPOWER discussion forum <[email protected]> > Date: Wednesday, May 4, 2016 at 8:49 AM > To: MATPOWER discussion forum <[email protected]>, > "[email protected]" <[email protected]> > Subject: Re: modification on Matpower case.m file for power flow of > distribution system > > Thanks Jovan, > > In Matpower there are no test cases for distribution systems... Where can i > find IEEE distribution system test cases? > > Regards > > > Have a nice day > > Regards, > FIAZ AHMAD > PhD Student, > FENS Sabanci University, > Istanbul Turkey > > > > On Wed, May 4, 2016 at 4:46 PM, Jovan Ilic <[email protected]> wrote: > > Fiaz, > > You are missing lots of data here. I suggest looking at IEEE distribution > system > test cases to see what is involved. Matpower is used for transmission > systems > not distribution systems. > > Jovan > > On Wed, May 4, 2016 at 3:45 AM, Fiaz Ahmad <[email protected]> wrote: > Hi. i have the following data files for ieee 33 bus radial distribution > system. i want to modify the case33.m file in matpower to carry out the power > flow of the above distribution system. Please guide me how can i achieve that. > > linedata33 > % Bus fbus tbus R X > 1 1 2 0.0922 0.0470 > 2 2 3 0.4930 0.2511 > 3 3 4 0.3660 0.1864 > 4 4 5 0.3811 0.1941 > 4 5 6 0.8190 0.7070 > 6 6 7 0.1872 0.6188 > 7 7 8 0.7114 0.2351 > 8 8 9 1.0300 0.7400 > 9 9 10 1.0440 0.7400 > 10 10 11 0.1966 0.0650 > 11 11 12 0.3744 0.1238 > 12 12 13 1.4680 1.1550 > 13 13 14 0.5416 0.7129 > 14 14 15 0.5910 0.5260 > 15 15 16 0.7463 0.5450 > 16 16 17 1.2890 1.7210 > 17 17 18 0.7320 0.5740 > 18 2 19 0.1640 0.1565 > 19 19 20 1.5042 1.3554 > 20 20 21 0.4095 0.4784 > 21 21 22 0.7089 0.9373 > 22 3 23 0.4512 0.3083 > 23 23 24 0.8980 0.7091 > 24 24 25 0.8960 0.7011 > 25 6 26 0.2030 0.1034 > 26 26 27 0.2842 0.1447 > 27 27 28 1.0590 0.9337 > 28 28 29 0.8042 0.7006 > 29 29 30 0.5075 0.2585 > 30 30 31 0.9744 0.9630 > 31 31 32 0.3105 0.3619 > 32 32 33 0.3410 0.5302 > > loaddata33 > %Bus P Q > 1 0 0 0 > 2 100 60 0 > 3 90 40 0 > 4 120 80 0 > 5 60 30 0 > 6 60 20 0 > 7 200 100 0 > 8 200 100 0 > 9 60 20 0 > 10 60 20 0 > 11 45 30 0 > 12 60 35 0 > 13 60 35 0 > 14 120 80 0 > 15 60 10 0 > 16 60 20 0 > 17 60 20 0 > 18 90 40 0 > 19 90 40 0 > 20 90 40 0 > 21 90 40 0 > 22 90 40 0 > 23 90 50 0 > 24 420 200 0 > 25 420 200 0 > 26 60 25 0 > 27 60 25 0 > 28 60 20 0 > 29 120 70 0 > 30 200 600 0 > 31 150 70 0 > 32 210 100 0 > 33 60 40 0 > > Please help and guide.... Thanks > > > > > > > > > >
