Dear All,

 

I am working on Modal Analysis. I would like to show to my students, that in
the bifurcation point at least one of the reduced Jacobian eigenvalues is
zero. This is why I calculate these values once for the base case and then
for the nose point ( lambda max calculated by the CPF). 

 

Unfortunately there is no change in the results. Could anyone help?

 

The results of the eigenvalues are as follows (for case14)

 

Eigb= 

[

65,4207

39,9533

21,9939

18,9118

16,4492

11,3421

2,70658

5,56886

7,66373

]

 

And exactly the same ones in the nose points.

 

I would greatly appreciate any help from you as I got terribly stuck.

 

Best,

Mariusz Drabecki

 

 

Here is my code:

 

define_constants

mpc=loadcase(case14);

inc=2.5;

 

%% CPF options

mpopt = mpoption('out.all', 0, 'verbose', 2);

mpopt = mpoption(mpopt, 'cpf.stop_at', 'NOSE', 'cpf.step', 0.1);

mpopt = mpoption(mpopt, 'cpf.plot.level', 2);

%% Base case (base solution operating points)

%CPF

mpcb=mpc;

mpct = mpcb; % set up target case with

mpct.gen(:, [PG QG]) = mpcb.gen(:, [PG QG]) * inc; % increased generation

mpct.bus(:, [PD QD]) = mpcb.bus(:, [PD QD]) * inc; % and increased load

cpf1 = runcpf(mpcb, mpct, mpopt);

lambda_max=cpf1.cpf.max_lam;

 

%Modal Analysis for Base Case

[jb11,jb12,jb21,jb22,jacb,~,~,~] = makeJac(mpcb);

jb11=full(jb11);

jb12=full(jb12);

jb21=full(jb21);

jb22=full(jb22);

Hb=jb11;

Mb=jb12;

Nb=jb21;

Kb=jb22;

% The reduced Jacobian for the base case (Q-V sensitivities)

jacb_red=Kb-Nb*inv(Hb)*Mb;

 

% The eigenvalues of the reduced Jacobian (Q-V sensitivities)

[leftb eigb rightb]=(eig(jacb_red));

 

%% Target case (nose point)

mpct.gen(:, [PG QG]) = mpct.gen(:, [PG QG]) * lambda_max; % increased
generation

mpct.bus(:, [PD QD]) = mpct.bus(:, [PD QD])* lambda_max; % and increased
load

% The  Jacobian for the target case

[jt11,jt12,jt21,jt22,jact,~,~,~] = makeJac(mpct);

jt11=full(jb11);

jt12=full(jb12);

jt21=full(jb21);

jt22=full(jb22);

njact=size(jact,1);

Ht=jt11;

Mt=jt12;

Nt=jt21;

Kt=jt22;

% The reduced Jacobian for the target case

jact_red=Kt-Nt*inv(Ht)*Mt;

% Eigenvalue decomposition of the reduced Jacobian for the target case

[leftt eigt rightt]=(eig(jact_red));

 

 

 

 

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