Dear all, I just check the case info and it went like this
K>> case_info(hop)
Checking connectivity ... single connected network, plus 2 isolated buses
Elapsed time is 0.243862 seconds.
================================================================================
Full Island Isolated
System 1 Buses
Number of: ---------- ---------- ----------
buses 64 62 2
loads 59 59 -
on 59 59 -
off - - -
fixed 59 59 -
dispatchable - - -
on - - -
off - - -
generators 3 1 2
on 3 1 2
off - - -
shunt elements - - -
branches 66 64 -
on 61 61 -
off 5 3 -
ties (off) 2 2 2
Load
active (MW)
dispatched 18.2 18.2 -
fixed 18.2 18.2 -
dispatchable - - -
nominal 18.2 18.2 -
on 18.2 18.2 -
off - - -
fixed 18.2 18.2 -
dispatchable - - -
on - - -
off - - -
reactive (MVAr)
dispatched 10.9 10.9 -
fixed 10.9 10.9 -
dispatchable - - -
nominal 10.9 10.9 -
on 10.9 10.9 -
off - - -
fixed 10.9 10.9 -
dispatchable - - -
on - - -
off - - -
Generation
active (MW)
dispatched - - -
max capacity - - -
on - - -
off - - -
min capacity - - -
on - - -
off - - -
reactive (MVAr)
dispatched - - -
max capacity - - -
on - - -
off - - -
min capacity - - -
on - - -
off - - -
Shunt Injections
active (MW) - - -
reactive (MVAr) - - -
Branch Losses
active (MW) - - -
reactive (MVAr) - - -
DC line
export (MW)
dispatch - - -
max capacity - - -
on - - -
off - - -
min capacity - - -
on - - -
off - - -
Reference Buses
num of ref buses 3 1 2
ref bus numbers 1 2 1
2 3
3
So what I need is no isolated bus, how to make the isolated bus becomes non
isolated bus? thank you.
On Thu, 11 Apr 2019, 05:04 Carlos A. Castro, <[email protected]> wrote:
> Dear Putu
>
> I have not run your whole program. I did run a power flow for the 64-bus
> system.
>
> The system is all connected, that is, there are no islands.
>
> The power flow runs smoothly, and converges after 3 iterations. My
> experience shows that Newton's method runs very well for distribution
> systems, contrary to some beliefs. Decoupled methods are the ones that may
> fail for distribution systems.
>
> I would suggest that you debug your program to see whether there is
> anything wrong with it. For instance, suppose that your program defines a
> branch to be opened, causing an island. The power flow would diverge in
> this situation. Actually, Matpower allows you to find it out before running
> a power flow, which is a very good thing to do.
>
> In short, the problem iis certainly not related to the system data.
>
> Regards,
>
>
>
> Em ter, 9 de abr de 2019 às 13:53, Nitya Kirana <[email protected]>
> escreveu:
>
>> Dear Carlos,
>>
>> Here is my program, please run it more than once, because the result will
>> be different for every run, thank you.
>> *Best Regards,*
>>
>> *Putu Diah Nitya Kirana,*
>>
>> Assistant and Researcher at Electric Energy Conversion Laboratory B101
>> Electrical Engineering Department
>> Faculty of Electrical Technology
>> Institut Teknologi Sepuluh Nopember
>> Surabaya, Indonesia
>>
>> +62 8170 3178 248
>>
>>
>>
>> On Tue, 9 Apr 2019 at 23:39, Carlos A. Castro <[email protected]> wrote:
>>
>>> Would you please send me de data file (.m)? I'll try to run it here.
>>>
>>> ---------- Forwarded message ---------
>>> De: Nitya Kirana <[email protected]>
>>> Date: ter, 9 de abr de 2019 às 01:53
>>> Subject: Re: Network Reconfiguration
>>> To: MATPOWER discussion forum <[email protected]>
>>>
>>>
>>> Dear Carlos A. Castro,
>>>
>>> Thank you before. I've done the replacement and the buses are all
>>> correct, because I draw the single line diagram first and then input the
>>> data in Matlab. Is there any other solution?
>>> *Best Regards,*
>>>
>>> *Putu Diah Nitya Kirana,*
>>>
>>> Assistant and Researcher at Electric Energy Conversion Laboratory B101
>>> Electrical Engineering Department
>>> Faculty of Electrical Technology
>>> Institut Teknologi Sepuluh Nopember
>>> Surabaya, Indonesia
>>>
>>> +62 8170 3178 248
>>>
>>>
>>>
>>> On Tue, 9 Apr 2019 at 00:47, Carlos A. Castro <[email protected]>
>>> wrote:
>>>
>>>> Dear Nitya
>>>>
>>>> I would do two things:
>>>>
>>>> 1. I would replace all commas "," by points "." in the data file.
>>>>
>>>> 2. I would try to draw the one line diagram of the network based on the
>>>> data, to check whether the network is all connected, that is, that there
>>>> are no isolated buses or group of buses,
>>>>
>>>> Good luck,
>>>>
>>>> Carlos
>>>>
>>>>
>>>> Em seg, 8 de abr de 2019 às 14:42, Nitya Kirana <
>>>> [email protected]> escreveu:
>>>>
>>>>> Dear all,
>>>>>
>>>>> I have run the power flow of 64 radial test bus system using Newton
>>>>> Raphson in Matpower 4.1. It shows the result of power losses but it
>>>>> doesn't converge, whenever I run the matlab, the result is always
>>>>> different, and I don't know what's the problem. Can anyone help me?
>>>>> because
>>>>> this is my final project. It shows "Warning: Matrix is singular to
>>>>> working precision."
>>>>>
>>>>> So, here is my data :
>>>>>
>>>>> bus data
>>>>> bus type Pd Qd Gs Bs
>>>>> area Vm Va baseKV zone Vmax Vmin
>>>>> 1 3 0 0 0 0 1 1 0 20 1 1 0,9
>>>>> 2 3 0 0 0 0 1 1 0 20 1 1 0,9
>>>>> 3 3 0 0 0 0 1 1 0 20 1 1 0,9
>>>>> 4 1 0,0136 0,016256 0 0 1 1 0 20 1 1 0,9
>>>>> 5 1 0,0204 0,024384 0 0 1 1 0 20 1 1 0,9
>>>>> 6 1 0 0 0 0 1 1 0 20 1 1 0,9
>>>>> 7 1 0,07684 0,091846 0 0 1 1 0 20 1 1 0,9
>>>>> 8 1 0,02856 0,034138 0 0 1 1 0 20 1 1 0,9
>>>>> 9 1 0,03808 0,045517 0 0 1 1 0 20 1 1 0,9
>>>>> 10 1 0,0238 0,028448 0 0 1 1 0 20 1 1 0,9
>>>>> 11 1 0,01768 0,021133 0 0 1 1 0 20 1 1 0,9
>>>>> 12 1 0,017 0,02032 0 0 1 1 0 20 1 1 0,9
>>>>> 13 1 0,022304 0,02666 0 0 1 1 0 20 1 1 0,9
>>>>> 14 1 0,0204 0,002438 0 0 1 1 0 20 1 1 0,9
>>>>> 15 1 0,05848 0,069901 0 0 1 1 0 20 1 1 0,9
>>>>> 16 1 0,26384 0,315366 0 0 1 1 0 20 1 1 0,9
>>>>> 17 1 0,03774 0,04511 0 0 1 1 0 20 1 1 0,9
>>>>> 18 1 0,0204 0,002438 0 0 1 1 0 20 1 1 0,9
>>>>> 19 1 0,05576 0,06665 0 0 1 1 0 20 1 1 0,9
>>>>> 20 1 0,0136 0,016256 0 0 1 1 0 20 1 1 0,9
>>>>> 21 1 0,0306 0,016256 0 0 1 1 0 20 1 1 0,9
>>>>> 22 1 0,0204 0,024384 0 0 1 1 0 20 1 1 0,9
>>>>> 23 1 0,0272 0,032512 0 0 1 1 0 20 1 1 0,9
>>>>> 24 1 0,11764 0,140614 0 0 1 1 0 20 1 1 0,9
>>>>> 25 1 0,0068 0,008128 0 0 1 1 0 20 1 1 0,9
>>>>> 26 1 0,0136 0,016256 0 0 1 1 0 20 1 1 0,9
>>>>> 27 1 0,0238 0,028448 0 0 1 1 0 20 1 1 0,9
>>>>> 28 1 0,112948 0,135006 0 0 1 1 0 20 1 1 0,9
>>>>> 29 1 0,02176 0,02601 0 0 1 1 0 20 1 1 0,9
>>>>> 30 1 0 0 0 0 1 1 0 20 1 1 0,9
>>>>> 31 1 0,01768 0,021133 0 0 1 1 0 20 1 1 0,9
>>>>> 32 1 0,05168 0,061773 0 0 1 1 0 20 1 1 0,9
>>>>> 33 1 0,03468 0,041453 0 0 1 1 <td align="right"
>>>>> style="padding-top:1px;padding-right:1px;padding-left:1px;color:black;f
>>>>>
>>>>
