Hello everyone, I have a question about calculating the losses parametres a, b and c with different voltages and nominal powers in matAC/DC , i know this platform is for matpower problems but i tried to put my question because i didn't find answers and maybe one of you can help me. I even contact Mat AC/DC developer and no one answer me. my base is the article ''Generalized steady state VSC MTDC model for sequential AC/DC power flow algorithms '' written by Jef Beerteen who developed Mat AC/DC. In this article he used the parametres a, b and c figured in table 1 ''VSC converter data'' (figure below) for different voltages and powers. I want to calculate these parametres by my self so i was based on the table of losses of the reference model Sodra Lanken which is rated at 600 MW and +/- 300 kV (the attached table sodra model.png ).
According to this table: * the constant losses who represents a are 6.62 MW, * the linear losses who represents b are 3*600V=1800V=1.8 KV is 600V mean 2*dc voltage = 2* 300 and if that true why the unity is V and not KV like the DC voltage . * square losses represents the Cint and the Crect so Crect= 3*0.66 = 1.98 ohm and Cinvt= 3*1 = 3 ohm. so for a converter with +/- 300kv and 100 MW: * i divide a=6.62 /6= 1.103 MW. because i guess the value of a is proportionnel with the nominal power.( but in your table in the article for converters 4,6 with 200 MW you have a=1.103 MW and for converters 5, 6 with 100 MW you have a= 2.206 !!!! why is not the opposite.????) * for b it remains the same but if we have a converter with +/- 150 KV, b= 3*2*150=3*300=900=0.9KV * the C values is inversely proportional to the nominal power so Crect = 1.98*6=11.88 ohm and Cint= 3*6=18 ohm is my logic true ..?? If anyone can help me please response me. Thank you ASMA
