-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Federica Fiorese wrote: > Hi! > to understand how to feed my patch antenna I'm trying > to realize a short circuit, so I feed the antenna and > I look what it radiates: being a short circuit I > expect to find no field. I implement this situation as > follow but I don't get correct result. Does it depend > on a mistake in the concept or in the implementation? > Thanks!! > Federica
It is a mistake in concept. In real life, most antennas are either open circuits or closed circuits at DC. At radio frequencies, the concept of closed circuit or open circuit does not really apply. > (set! sources (list (make source > (src (make continuous-src (frequency 16.6))) > (component Ey) > (center 0 (/ (+ h hm) 2) (- (/ L 2) 0.1e-6))))) If your frequency were 0 instead of 16.6, then this might be a short circuit. However, in that case an _infinite_ amount of current would flow, since you have set a fixed electric field and there is no resistance. - --Ben -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.7 (GNU/Linux) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iD8DBQFHsFf5UJT6e6HFtqQRAvPNAKCM8HIAEtkh+7tGep8sENwRCDlu/QCePfaw 17SccQnPcOMciipZbqFQJ2o= =BJws -----END PGP SIGNATURE----- _______________________________________________ meep-discuss mailing list [email protected] http://ab-initio.mit.edu/cgi-bin/mailman/listinfo/meep-discuss
