Yes I understand, I didn't explain clearly what I wanted to achieve with x.
It now works with the modified structure below. I create an additional
variable which I set to be x within the loop.
Hence it becomes global and can now be called outside the loop without
using a procedure taking an argument (calling x directly outside the
loop produces an "undefined" error). So the name itself of the function
can be called with run-until.
Please let me know if there is a better way of doing that.
(define xtest 0)
(define (print-all) (print "x=" "," xtest "\n"))
(do ((x xstart (+ x xstep))) ((> x xstop))
; setting the structure, source etc
(set! xtest x)
(run-until 1 (at-end print-all))
(reset meep)
)
I hope this can be of help.
Regards,
Fred
Steven G. Johnson wrote:
> On Sep 23, 2008, at 7:22 PM, Frederic Brossard wrote:
>
>> (define (print-all x) (print "x=" "," x "\n"))
>> (do ((x xstart (+ x xstep))) ((> x xstop))
>> ; setting the structure, source etc
>> (run-until 1) (at-end (print-all x))
>> (reset-meep)
>> )
>> generates an error. No error if (print-all x) is called within the
>> loop
>> but outside run-until or if run-until is not a function of the
>> variable
>>
>
> I'm guessing that you mistyped it in your email, and your code looks
> like:
>
> (run-until 1 (at-end (print-all x)))
>
> This won't work because (print-all x) is not a function, it is the
> result of calling a function.
>
> See:
>
> http://ab-initio.mit.edu/wiki/index.php/The_run_function_is_not_a_loop
>
> Steven
>
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