Hi Steven and meep users:
I try to figure out the product of the temporal width and frequency width
since when I submit a job, I have to specify running time.
Based on the pulse source in the Meep reference:
exp( − iωt − (t − t0)2 / 2w2),
omega is the inverse of the wavelength
t0= cutoff * w, temporal width.
w=temporal width.
I usually specify the frequency bandwidth df,
So I wonder the relation of the df and w since I know that product is
different by different definition. Which one is used in Meep?
Thank you
Regards
Adrian
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