Thank you very mucho for every answers. You help me a lot since I was very very lost, but I return to ask new questions, xD.
Best wishes, Alejandro Escuín From: [email protected] To: [email protected] Date: Mon, 18 Oct 2010 17:45:22 +0200 Subject: [Meep-discuss] Very lost with Meep Units Hello Everybody, I'm researcher working about computacional electromagnetic and I am probing Meep to watch the behaviour of the software, but I don't understand very well the Unit in Meep. I think that I understand the meaning of 'a' and 'c', but I don't know if I am using it well. For example, if I want to simulate a perfect cube with the following characteristics: - side = 150um - source = continuous => Sine wave - frequency = 15 e13 - lambda = 6 e-6 Since my lambda is 6 e-6, I take 'a'= 1 e-5, so lambda_meep=0.6, and frequency is 1/lambda. With this value, if the size of my stucture is 150um, the size is 15 a's = 15*(1 e-5) = 150 e-6. Have I got any error? Moreover, I want a total of 100 Yee lattice, so I have to set the resolution to 6.666. Explication: 15*resolution = 100 cells, so resolution = 100/15, no? I'm a bit lost, please, I need your help. Thank you very much. Alejandro Escuín _______________________________________________ meep-discuss mailing list [email protected] http://ab-initio.mit.edu/cgi-bin/mailman/listinfo/meep-discuss
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