Hi Mike

None is not the same as int(0) - it's a bit like javascript's NaN
(not-a-number); it's not 0, it's a complete absence of value; an
indeterminate value. Because of this, it can't actually be successfully
cast to a numeric:

>>> a = None
>>> int(a)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: int() argument must be a string or a number, not 'NoneType'

Python 3's a bit stricter about trying to compare incomparable types (See
e.g.
http://stackoverflow.com/questions/8961005/comparing-none-with-built-in-types-using-arithmetic-operatorsfor
more). The way to correctly compare to None is to use "is", ie:

>>> a = None
>>> b = 1
>>> if a is not b:
...     print("woo")
...
woo

Cheers

Chris


On Fri, Feb 7, 2014 at 6:21 PM, Mike Dewhirst <[email protected]> wrote:

> It is in Python 2.7 ...
>
> Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (Intel)]
> on win32
> Type "help", "copyright", "credits" or "license" for more information.
> >>> foo = None
> >>> bar = 2
> >>> foo < bar
> True
> >>>
>
> But it seems not in Python 3.3 ...
>
> Python 3.3.3 (v3.3.3:c3896275c0f6, Nov 18 2013, 21:18:40) [MSC v.1600 32
> bit (Intel)] on win32
> Type "help", "copyright", "credits" or "license" for more information.
> >>> foo = None
> >>> bar = 2
> >>> foo < bar
> Traceback (most recent call last):
>   File "<stdin>", line 1, in <module>
> TypeError: unorderable types: NoneType() < int()
> >>>
>
> Should I rtfm?
>
> Maybe there is a trick to it?
>
> Thanks
>
> Mike
>
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