Excerpts from Jun Wu's message of 2017-03-21 22:42:11 -0700: > The key here is the order of operation 2 and 3. If 2 happens after 3, then B > gets hidden as expected. Currently, this cycle will get both B and C hidden, > which I don't think is a sane behavior.
Sorry. It should be "Currently, 3 is always treated as happened before 2". There are no cycles in this simple case. _______________________________________________ Mercurial-devel mailing list Mercurial-devel@mercurial-scm.org https://www.mercurial-scm.org/mailman/listinfo/mercurial-devel
