Hi gaurav ,

I guess  for Feb 31 also will get accepted for. what is the solution

and for year pattern *  [19][20]\d\d  which is easy to remember*





On Fri, Feb 22, 2013 at 8:28 AM, gaurav sharma <[email protected]> wrote:

> *Hi Nataliya,
>
> Please find below the reg expression format u asked:-*
>
> *Format: MM/DD/YYYY
>
> MM: (0[1-9]|1[0-2])
>
> DD: (0[1-9]|1[0-9]|2[0-9]|3[0-1])
>
> YYYY: ([0-9][0-9][0-9][1-9]|[1-9]000|[1-9][1-9]00|[1-9][1-9][1-9]0)*
>
> * Assuming that Max year is 9999
> *
> Format: HH/Min
> *
> *Hours: ([0-1][0-9]|2[0-3])
>
> Mins: ([0-5][0-9])
>
> Regards,
> Gaurav
>
> *
> On Wed, Feb 20, 2013 at 10:45 PM, Punj Prakash <[email protected]>wrote:
>
>> Please use regular expression.
>>
>> Thanks,
>> Punj
>>
>>
>> On Wed, Feb 20, 2013 at 10:13 PM, Nataliya Zamaray <
>> [email protected]> wrote:
>>
>>>             I need to insert some kind of checkpoint to verify that
>>> the format is mm/dd/yyyy  hh:min
>>>
>>>
>>> 12/10/2012 1:28 PM EST.
>>>
>>> Any suggestion?
>>>  I appreciate any help from the group
>>>  Thanks
>>>
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>
>
> --
> GAURAV SHARMA
> S/W ENGG.
> ACCENTURE
>
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-- 


* *
*Best Regards*
*reddy prasad*
*9742372795*
*9886293685*

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