this will work only if the value is in a single string format...

On Tue, Oct 8, 2013 at 11:36 AM, uma mahesh <[email protected]> wrote:

> One more simple logic:-
>
> myarr="bb aa cc gg hh tt gg bb aa 44 55 77 66 22 55 44 88 77 66 22 44"
> myarr=split(myarr, " ")
>
> for i=0 to ubound(myarr)
>
>     if instr(newarr, myarr(i))=0 then
>         newarr=newarr & myarr(i) & " "
>     End if
>
> Next
>
> msgbox newarr
> newarr=split(newarr, " ")
>
>
>
>
> Regards
> Uma Mahesh
>
>
> On Mon, Oct 7, 2013 at 8:39 PM, Amit Kumar <[email protected]>wrote:
>
>> another logic...
>>
>> Dim arr, res(), temp, count1
>> count1=0
>> arr=array(11, 11, 12, 13, 14, 13, 11)
>> ReDim preserve res(0)
>> res(0)=arr(0)
>> For i=1 to ubound(arr)
>>     j=0
>>     Do while j <= ubound(res)
>>         If arr(i) = res(j) Then
>>             Exit do
>>         End If
>>         j=j+1
>>     Loop
>>
>>     If j > ubound(res) Then
>>         count1=count1+1
>>         ReDim preserve res(count1)
>>         res(count1)=arr(i)
>>     End If
>> Next
>>
>> For i=0 to ubound(res)
>>     print res(i)
>> Next
>>
>>
>>
>> On Mon, Oct 7, 2013 at 4:21 PM, Amit Kumar <[email protected]>wrote:
>>
>>> you can write the simpler one.
>>>
>>> Dim arr, res(4), temp, count1
>>> count1=0
>>> arr=array(11, 22, 33, 44, 22, 44, 55, 11)
>>> For i=lbound(arr) to ubound(arr)
>>>     temp=i
>>>     For j=i+1 to ubound(arr)
>>>         If arr(i)<>arr(j) Then
>>>             temp=temp+1
>>>         End If
>>>     Next
>>>     If temp=ubound(arr) Then
>>>         res(count1)=arr(i)
>>>         count1=count1+1
>>>     End If
>>> Next
>>>
>>> For i=0 to count1-1
>>>     print res(i)
>>> Next
>>>
>>> Thanks,
>>> Amit
>>>
>>>
>>> On Mon, Oct 7, 2013 at 3:27 PM, Venkat Kandula <
>>> [email protected]> wrote:
>>>
>>>> Hi Experts,
>>>>
>>>> I need a script for the below question.
>>>>
>>>> How to find the duplicate values in an array and Delete the Duplicate
>>>> values from the array.
>>>>
>>>> Thanks,
>>>> Venkat
>>>>
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