At 10:49 AM 3/2/99 -0800, Paul Leyland wrote:
>I really must proof-read more carefully before posting. 0 is *not* a valid
>exponent. The other two are, though 1 is trivial and it's easy to give an
>infinite set of solutions for n=2. The non-trivial bit is proving that
>these are the only exponents.
Actually n=2 is trivial too. You don't have to show that there are an infinite
number of solutions (in positive integers) for n=2, you only need to show one,
e.g. 3^2 + 4^2 = 5^2.
+-----------------------------------------------------------+
| Jud McCranie [EMAIL PROTECTED] |
| |
| "We should regard the digital computer system as an |
| instrument to assist the number theorist in investigating |
| the properties of his universe - the natural numbers." |
| -- D. H. Lehmer, 1974 (paraphrased) |
+-----------------------------------------------------------+
________________________________________________________________
Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm
