> From: "Brian J Beesley" <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED]
> Date: Thu, 7 Jan 1999 14:59:26 GMT
> MIME-Version: 1.0
> Content-transfer-encoding: 7BIT
> Subject: Re: Mersenne: Re: Spin Structures on Riemann Surfaces
> Content-Transfer-Encoding: 7BIT
>
> Date sent: Thu, 7 Jan 1999 08:33:56 +0100 (MET)
> > >If an odd number N has a factor F < N, then N can be expressed as the sum
of F
> > >consecutive integers, as follows: Let Q = N/F and D = (F-1)/2, then
> > >
> > >N = (Q-D) + (Q-D+1) + ... + Q + ... + (Q+D-1) + (Q+D).
> >
> > I guess, its F that has to be odd and not N.
>
> Duh.... the line N= has 2D+1 terms - therefore N must be _odd_
> since the terms are (consecutive) integers
>
> It _follows_ that F is odd, too: (given) D=(F-1)/2, if F is even, D isn't
> an integer; also, an odd number can't have even factors...
>
>
>
> Regards
> Brian Beesley
N doesn't have to be odd, for example N = 12, and F=3 than Q=4, D=1 and
12 = 3+4+5
Clearly this is not ODD !!
Regards
Benny
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Benny Van Houdt,
University of Antwerp
Dept. Math. and Computer Science
PATS - Performance Analysis of Telecommunication
Systems Research Group
Universiteitsplein, 1
B-2610 Antwerp
Belgium
email: [EMAIL PROTECTED]
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