Mersenne Digest        Saturday, June 26 1999        Volume 01 : Number 588




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Date: Thu, 24 Jun 1999 09:54:34 -0700
From: Paul Leyland <[EMAIL PROTECTED]>
Subject: RE: Mersenne: safe to defrag?

> From: Jud McCranie [mailto:[EMAIL PROTECTED]]

> Since Prime95 writes to the disk periodically, is it safe to do a disk
> defragmentation while it is running?

That, of course, depends on how good your defragger is.  Personally, I
wouldn't use a defragger that can't be trusted to leave the disk usable,
even if disk activity is occurring.

I won't make any product recommendations and, despite my email address, the
contents of this mail is entirely my personal view and not that of a certain
software company.  However, I will say that I use / have used a variety of
defraggers and Prime95 concurrently on Win9x, NT 4.0 at various service pack
levels, and Win2k beta 3.

Your milage may vary.

Paul
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Date: Thu, 24 Jun 1999 13:12:49 EDT
From: [EMAIL PROTECTED]
Subject: Mersenne: Defragmenting and Security

<<I have mine configured to be a tray icon, which generally goes unnoticed or 
is ignored.>>
How about the No Icon option? (You can still access it by trying to run 
Prime95.exe again). And have it configured as a Win95 service. I'm not sure 
if my system is an anomaly, but even the Three-Fingered Salute doesn't show 
Prime95 to be on the list of tasks to shut down. If the weasel who stole your 
laptop doesn't look hard enough, he will then have almost no chance of 
finding the program. Heh.

In regards to defragmenting: I have defragmented my C hard drive (where 
Prime95 runs) a number of times, and it almost always takes over 30 minutes, 
which is how long Prime95 waits before writing save files. MS Defrag (taken 
from Symantec - look at the copyright notice!) is just as well-behaved as 
good old FAT16 Symantec Norton Utilities' defragmenter. Apparently, when a 
program writes to the HD, MS Defrag detects it and rescans the hard drive's 
contents. No errors are produced. If you are using a Symantec product, then 
it will also be well behaved. I don't know about other programs or non-Win95 
systems.

STL
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Date: Thu, 24 Jun 1999 14:36:28 -0400
From: "Silverman, Bob" <[EMAIL PROTECTED]>
Subject: Mersenne: RE: Mersenne Digest V1 #587

Regarding the discussion about the distribution of M_p:

Sam Wagstaff's results imply that the expected number of
Mersenne primes between  2^h  and  2^2h  is exp(gamma).
Thus, they DO get progressively rarer.

Further, by the PNT,  the probability that a random integer
near x is prime is 1/log(x).   *ASSUMING* that 2^p-1 behaves
like a random integer, the probability that it is prime should
be 1/p log(2).   

Now,  sum from 2 to k  of 1/p is asymptotically 
loglog k  [this is easy;  p_n ~ n log n  from PNT, so
by Stieltje's integration (or Euler-Maclauren) on gets
sum from 2 to k of 1/p =  integral from 2 to k of 1/(n log n) d [n].
Now integrate by parts. ]

Thus, one should expect that the number of Mersenne primes up to
k  is O(log log k).

Be wary of what Richard Guy calls the law of small numbers...
Most number-theoretic phenomena only show their true behavior for
VERY large numbers and we are not there yet.  To put it another way,
as John Selfridge said:  although we know loglog n  goes to infinity,
it has never actually been observed to do so...


BTW,  there is nothing unique about base 2 in this regard.  We
should expect that  the number of primes of the form  (a^p - 1)/(a-1)
up to k is O(log log k)  for all a.  The only thing that changes
is the implied constant.  

Bob Silverman
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Date: Thu, 24 Jun 1999 15:20:33 -0400 (EDT)
From: lrwiman <[EMAIL PROTECTED]>
Subject: RE: Mersenne: Once again factoring

> Exactly.  I knew that 1/p number didn't look right.  Isn't it more like
> 1/sumof(all p < current p)?

The method that I used (I think I got it from _Primes and Programming_ by 
Peter Glibin) is that for any given set of primes, the probability that any 
number greater than them will be divisable by at least one of them is
~1-prod((p_i-1)/p_i). 

The probability that any given prime p will divide another (>=2*p) is 1/p.
Therefore, the probability that it will not be divisable is (p-1)/p.
Now to get the probability that the number will not be divisable by two primes
p_1 and p_2, we multiply the individual probabilities that  they do not divide
=(p_1-1)*(p_2-1)/(p_1*p_2).  Therefore to find the probaility that they do
divide (since prob. of divisability +prob of nondivisability=1), we take 
1-(prob that they do not divide)=1-(p_1-1)*(p_2-1)/(p_1*p_2), and so on
for p_3,p_4....p_n.  Note that this primes do not have to be in numerical order
after a time, for suficiently many primes the only ones missed will be powers 
of the primes not included which are very insignificant statistically.

We can also use this method as a slight alteration of Euclid's proof for an
infinity of primes, which I leave as an excersize for the readers ;)
- -Lucas Wiman
P.S.  This is not rigorously proven, and might not take into account certain
things like numbers divisable by p_1*p_2*p_3 or something like that.

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Date: Thu, 24 Jun 1999 16:55:59 -0400
From: Jud McCranie <[EMAIL PROTECTED]>
Subject: Mersenne: Mersenne Distribution

At 02:36 PM 6/24/99 -0400, Silverman, Bob wrote:

>Regarding the discussion about the distribution of M_p:
>
>Sam Wagstaff's results imply that the expected number of
>Mersenne primes between  2^h  and  2^2h  is exp(gamma).
>Thus, they DO get progressively rarer.

This sounds right.  This corresponds to the c^n law, where c =
e^(log(2)/e^gamma) = 1.47576, which is also in better agreement with the
current data than c=3/2 (and 3/2 has no justification either).  I'd put my
money on Wagstaff's estimate.


+----------------------------------------------+
| Jud "program first and think later" McCranie |
+----------------------------------------------+


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Date: Thu, 24 Jun 1999 18:03:17 -0400 (EDT)
From: lrwiman <[EMAIL PROTECTED]>
Subject: Re:  Mersenne: Mersenne Distribution

> This sounds right.  This corresponds to the c^n law, where c =
> e^(log(2)/e^gamma) = 1.47576, which is also in better agreement with the
> current data than c=3/2 (and 3/2 has no justification either).  I'd put my
> money on Wagstaff's estimate.

This would put the 38th mersenne at ~2.6million, the 39th at ~3.9million,
and the 40th at 5.7million.  I don't know much about statistics, but this
seems like a bad match.  Could it be that the form should be of c^(a*n+b), and
the first few values might be anomalies for some reason?

- -Lucas Wiman

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Date: Thu, 24 Jun 1999 18:04:35 -0400
From: Peter Doherty <[EMAIL PROTECTED]>
Subject: RE: Mersenne: safe to defrag?

At 09:54 06/24/1999 -0700, you wrote:
>> From: Jud McCranie [mailto:[EMAIL PROTECTED]]
>
>> Since Prime95 writes to the disk periodically, is it safe to do a disk
>> defragmentation while it is running?

My computer is up 24/7.  Prime95 writes to disk every 30 minutes, and my
email program (Eudora) checks for new mail every 20 minutes.  Three times a
week my computer automatically runs Win98 defrag program to defrag all
7.5GB of HDD space (a 4.3 HDD, and a 3.2HDD)  I've never had any real
problem.  Everytime something writes to disk defrag restarts, scans for
errors, and then checks over all that it has defraged, and picks up where
it left off.  This takes 1 to 2 minutes.  I've had some unexplained
computer hangs while defragging, but I can't attribute that to Prime95.  So
that's the long.
The short is, it's entirely safe to defrag while running Prime95.

- --Peter

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Date: Thu, 24 Jun 1999 15:44:44 -0700
From: Luke Welsh <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Date: Thu, 24 Jun 1999 09:01:14 -0600

At 08:02 AM 6/24/99 -0700, you wrote:
>     ERROR:  Primenet error:  12029
>
>Can someone help me with the meaning of this particular
>message.

See http://entropia.com/ips/faq.html

- --Luke

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Date: Thu, 24 Jun 1999 22:25:28 -0400
From: Jud McCranie <[EMAIL PROTECTED]>
Subject: Re:  Mersenne: Mersenne Distribution

At 06:03 PM 6/24/99 -0400, lrwiman wrote:

>This would put the 38th mersenne at ~2.6million, the 39th at 
~3.9million,
>and the 40th at 5.7million. 

It doesn't work quite that way.  It is a global property that doesn't say
anything about the individual Mersenne primes, just as the Prime Number Theorem
applies to the distribution of primes as a whole, but doesn't tell you about
individual primes.

+----------------------------------------------+
| Jud "program first and think later" McCranie |
+----------------------------------------------+


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Date: Fri, 25 Jun 1999 12:04:52 -0400
From: "Ernst W. Mayer" <[EMAIL PROTECTED]>
Subject: Mersenne: Ernst's CA or bust deal (Was: M#38)

Dear Mersenners:

This being the sesquicentennial of the California gold rush,
I thought a fitting tribute would be to move there, this time
to be nearer the silicon, rather than the gold. I was going to
insert an Au-ful pun here, but couldn't come up with one. Si-gh...

As of 1 july, my left coast address is
     
Ernst W. Mayer
10190 Parkwood #1
Cupertino, CA 95014
     
And of course you can always use my "permanent" E-address, <[EMAIL PROTECTED]>.

I'd like to thank George W. for giving me the opportunity to verify M#38,
(I don't normally do double-checking, but in this case decided to make an
exception :) and David Willmore for use of his employer's Alpha 21264 for
the two-week-long run.

I won't have a chance to finish the production version of the prototype
code David used for his run (about 20% faster than my current production
Mlucas code) until I'm settled into my new apartment, but that'll give you
all time to order your own 21264's (about $7500 per CPU via microway.com,
but perhaps GIMPSers can get a volume discount - at the above price, it's
still far cheaper than an equivalent MIPS).

And I see that the movers are here, so I must prepare to take nigel off-line.

Cheers,
Ernst
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Date: Sat, 26 Jun 1999 02:37:51 -0400 (EDT)
From: Lucas Wiman  <[EMAIL PROTECTED]>
Subject: Mersenne: Still more 10,000,000+ digit factors!!!!!!!

I have found 1868 new factors in the range of Brian's 10,000,000+ digits.
All of the other primes in this range have been tested through 2^47.

They are avalaible at:
http://www.tasam.com/~lrwiman/fact47
or
http://www.tasam.com/~lrwiman/fact47.gz 

- -Lucas Wiman
P.S. If these posts are getting annoying, at least they will be getting less
frequent.
P.P.S. Does anybody but Will care about these new factors?
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Date: Sat, 26 Jun 1999 09:26:52 -0500 (CDT)
From: Conrad Curry <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Once again factoring

On 23 Jun 99, at 6:17, Brian J. Beesley wrote:
> 
> On 22 Jun 99, at 17:38, Gary Diehl wrote:
> > 2.  Why use a table at all?  Is it faster than doing a calculation to
> > determine if [f % 255255] != 0 ?  (I know sometimes tables can speed
> > things up, but does it really help with so few numbers involved in the
> > table?)


  Calculating f % 255255 does not tell us if f is divisible by
3, 5, 7, 11, 13 or 17 but only their product.  You would want to
test if GCD (f, 255255) > 1.


> On a Pentium, recalculating the index & looking up the table takes of
> the order of 20 clocks (allowing for a cache miss on the table read),
> irrespective of the size of f, whereas just dividing f by 255255 to
> get the remainder costs 39 clocks, even if f/255255 < 2^32.


  If f = 2*k*P + 1 is a potential factor of 2^P-1, then we can calculate
s[i] == -(p[i] + 1)/2 (mod p[i]) where p[i] are the primes 3, 5, 7, ...
Then solve the linear congruence P * c[i] == s[i] (mod p[i]) for c[i].
To test if f is divisible by p[i] test if k == c[i] (mod p[i]).
That reduces the dividend from f to k.  The division can be done by
multiplication by the reciprocal of p[i], this and c[i] can be
precomputed.

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Date: Sat, 26 Jun 1999 13:32:26 -0400
From: Jud McCranie <[EMAIL PROTECTED]>
Subject: Mersenne: Distribution of Mersenne primes

For those of us who don't have access to Wagstaff's 1983 paper "Divisors of
Mersenne Numbers", it is nicely summarized in "The New Book of Prime Number
Records", by Paulo Ribenboim, chapter 6, section V.A. (page 411-413 in this
edition).  He gives 3 statements:

(a) The number of Mersenne primes < x is about log(log(x))*e^gamma/log(2)

(b) the expected number of Mersenne primes between x and 2x is about e^gamma. 
(equivalent to part a)

(c) the probability that Mq is prime is about c*log(aq)/q where
c=e^gamma/log(2) and a=2 if q = 1 mod 4; a=6 if q=1 mod 4.

It gives fours considerations upon which Wagstaff's conjecture is based.  Of
course, these imply that the nth Mersenne number is about [2^(-gamma)]^n, or
1.4759^n.  

He goes on to mention Eberhart's earlier conjecture of (3/2)^n, but states that
there is no serious reason supporting this version of the conjecture.

+----------------------------------------------+
| Jud "program first and think later" McCranie |
+----------------------------------------------+


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End of Mersenne Digest V1 #588
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