At 23:26 14.07.99 -0400, Lucas Wiman wrote: >> Speaking of Q2.6, I've heard that with Crandall's DWT, the subtraction >> 2 step costs nothing at all. It's done automatically within the >> transformation. Try checking this with George Woltman. >Is this true? Not knowing for certain; I thought the DWT did the modulo for you, not the subtraction? /* Steinar */ ________________________________________________________________ Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm
- Mersenne: subtracting 2: error in FAQ Lucas Wiman
- Re: Mersenne: subtracting 2: error in FAQ Steinar H. Gunderson
- Re: Mersenne: subtracting 2: error in FAQ Henrik Olsen
