> Can somebody give me the last few digits of the decimal expansion of > (2^6972593)-1 so that I can verify my copy's intact ? to find the last n base-d digits of M39, find 2^(6972593) (mod 10^d) -1 The last 100 digits of it are: 854323570491331747687718276359853562553418155924593120827624505017498840034615135366526142924193791 -Lucas _________________________________________________________________ Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm Mersenne Prime FAQ -- http://www.tasam.com/~lrwiman/FAQ-mers
