> At 12:33 AM 11/5/99 +0000, Daniel Grace wrote:
> >"Polynomial?"
> >
> >I think and please correct if I am wrong that trial factorisation
> >using long division requires O(sqrt(n)*log(n)) operations.
>
> Jud McCranie wrote :
> It means that it is a polynomial function of the number of bits in
> n.

... or nibbles, bytes or whatever base your machine is working in ...
basically whatever you consider as requiring O(1) operations - it
does not effect the "O" analysis.

> Trial factorization isn't polynomial in the number bits of the number.

I did not say it was.

Daniel.


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