Mersenne Digest       Sunday, February 27 2000       Volume 01 : Number 698




----------------------------------------------------------------------

Date: Thu, 24 Feb 2000 20:04:21 EST
From: [EMAIL PROTECTED]
Subject: Mersenne: Re: Into the shadow of Death Valley rode the P100

John Pierce wrote:

>I've retired that 
>processor now as its time per exponent is just too
>high (besides its running linux now and I've never
>bothered to figure out the linux client).

I had a similar frustration with my trusty old P120 laptop once
first-time LL tests exponents started getting around 7M and more.
I adopted the "amphetamine drip" solution: removed the keyboard from
the laptop, slapped an extra heatsink and 12VDC cooling fan on top
of the alu. plate sitting atop the CPU, fiddled with the clock multiplier
jumper settings, and since then it's been running stably at 180MHz.
It isn't exactly pretty, but I've found a separate full-sized PS/2
keyboard easier to use anyway, and being able to do a 9M-range
exponent in 3.5 months rather than 5 is nice.

If i do need to go mobile (which is infrequent, it takes only a few
minutes to restore the original configuration and turn the clock
back down to 120MHz. Of course, it's running Win95, so I don't have
to deal with the Linux client, although others seem to have done so
without too much pain.

- -Ernst

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------------------------------

Date: Thu, 24 Feb 2000 17:57:49 -0800
From: "John R Pierce" <[EMAIL PROTECTED]>
Subject: Mersenne: Re: Into the shadow of Death Valley rode the P100

> >I've retired that 
> >processor now as its time per exponent is just too
> >high (besides its running linux now and I've never
> >bothered to figure out the linux client).
> 
> I had a similar frustration with my trusty old P120 laptop once
> first-time LL tests exponents started getting around 7M and more.
...

well, said former p100 now running linux is actually my home
firewall/gateway/web/mail/ftp server so I'd rather not be
running primexx on it anyways.

- -jrp


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------------------------------

Date: Thu, 24 Feb 2000 21:17:48 -0500
From: "Rick Pali" <[EMAIL PROTECTED]>
Subject: RE: Mersenne: Re: Into the shadow of Death Valley rode the P100

From: John R Pierce

> well, said former p100 now running linux is actually
> my home firewall/gateway/web/mail/ftp server so I'd
> rather not be running primexx on it anyways.

Just curious, but why? Would mprime compromise the security of that system
in any way?

Rick.
- -+---
[EMAIL PROTECTED]
http://www.alienshore.com/

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------------------------------

Date: Fri, 25 Feb 2000 13:45:31 +1100
From: Simon Burge <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Re: Into the shadow of Death Valley rode the P100 

"John R Pierce" wrote:

> well, said former p100 now running linux is actually my home
> firewall/gateway/web/mail/ftp server so I'd rather not be
> running primexx on it anyways.

If it's a low-traffic firewall there'll be truck loads of spare CPU
cycles :-)

Simon.
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------------------------------

Date: Thu, 24 Feb 2000 21:12:07 -0800
From: "John R Pierce" <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Re: Into the shadow of Death Valley rode the P100

> > well, said former p100 now running linux is actually
> > my home firewall/gateway/web/mail/ftp server so I'd
> > rather not be running primexx on it anyways.
>
> Just curious, but why? Would mprime compromise the security of that system
> in any way?

its memory limited and I don't want any more swapping than
absolutely necessary, my internet connect is a brisk 768k
SDSL.  Anyways, a pentium 100 is hardly gonna matter anymores,
I'm cranking nearly 600 P90 CPU hours per day as it is on other
much faster machines (mostly p2-400s and better)

- -jrp


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------------------------------

Date: Fri, 5 Mar 1999 20:07:26 +0100
From: Attila Megyeri <[EMAIL PROTECTED]>
Subject: Mersenne: Specific exponent reservation

Hi,

Is it possible to reserve a specific exponent through Primenet?  I would like
to test an exponent that is not randomly assigned to me but don't want to
loose the credit for it on my Primenet account.

Thanks,

Attila
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------------------------------

Date: Fri, 25 Feb 2000 08:26:48 -0500
From: "Nayan Hajratwala" <[EMAIL PROTECTED]>
Subject: Mersenne: (2^2^n) + 1

Hi Folks... can anyone help Ryan out?

- -----Original Message-----
From: RL Penter [mailto:[EMAIL PROTECTED]] 
Sent: Thursday, February 24, 2000 7:07 PM
To: [EMAIL PROTECTED]
Subject: 


Hey, 
  my name is Ryan Penter and I am currently studying Maths at Loughborough
University in England.  I was wondering if you could help me with a
problem; I need to find the largest known prime of the form:
                (2^2^n)+1      
congratulations by the way on finding the largest Mersenne prime!!!  
                any help would be amazing, thanx for your time,
                                                Ryan 

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------------------------------

Date: Fri, 25 Feb 2000 14:56:31 +0000
From: Alexander Kruppa <[EMAIL PROTECTED]>
Subject: Re: Mersenne: (2^2^n) + 1

Nayan Hajratwala wrote:

>
> problem; I need to find the largest known prime of the form:
>                 (2^2^n)+1
> congratulations by the way on finding the largest Mersenne prime!!!

These are Fermat numbers, Fermat conjectured that all numbers of this form
would be prime and proved it for
F_0=3, F_1=5, F_2=17, F_3=257,F4=65537.

However, not a single prime beyond those 5 has been found so far, all 4 < n
<31, and many >31, are proved composite. It is commonly believed that indeed
there is not a single Fermat prime except the first five. Find another one
and you'll be famous!

See http://www.perfsci.com/prizes.html for a Fermat factoring contest,
www.mersenne.org/ecmg.htm for current ECM factoring limits on Fermat numbers,

and http://vamri.xray.ufl.edu/proths/fermat.html for overall status of Fermat
numbers (prime, genuine composites, some factors known, completely factored)

Ciao,
  Alex.

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------------------------------

Date: Fri, 25 Feb 2000 14:58:36 +0000
From: Alexander Kruppa <[EMAIL PROTECTED]>
Subject: Re: Mersenne: (2^2^n) + 1

>www.mersenne.org/ecmg.htm for current ECM factoring limits on Fermat numbers,

Oops, should read: ecmf.htm

Ciao,
  Alex.
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------------------------------

Date: Fri, 25 Feb 2000 15:23:17 +0100
From: Reto Keiser <[EMAIL PROTECTED]>
Subject: Mersenne: p-1 and trial factoring

hi all

parallel use of p-1 and trial factoring
- ---------------------------------------

george suggested to run a p-1 test and trial factoring test before
ll-testing an exponent in version 20.

The possible factors are approximately logarithmic distributed, that
means there are about as many 66, 67 and 68 bit factors in the same
range. But the calculating time increases exponentially. So a computer
spends about the same time in finding 68 bit factors than factoring up
to 67 bits.
So it makes sense to factor up that length, where P[finding a factor
with n bits] = n-bit-factoring-time / ll-testtime.
So testing up to 68 factors should not take more time than (1/34) of an
ll-test. Most of the factors are found in the first part of the test.

using the p-1 factoring we have the same situation:
Using a B1 value of 50000 finds more factors than continuing from 50000
to 100000.

Why can't we do first first the factorization up to n-2 bits (1/4) of
the trial factoring time, then start the P-1 factoring up to 1/3 of the
B1 value, after this, we can complete the trial factoring process and at
the end we complete the P-1 (using the save file od intermediate file).
(the parameters can be optimized)

If one person runs the whole test, it is also possible that the computer
performs the stage 2 during the night when the computer is not in use
and Prime95 can use most of the memory.

no 68 bit factors
- -----------------

until now >210 factors are found for 10megadiginumbers and more than 280
exponents were factored up to 68 bits.
Some (about 7) 67 digit factors were found but none with 68 bits.
The value in the cleared exponent list is rounded to the next digit
round(log2(factor)) so that only factors >67.5 bits are declared as 68
bits and factors from 66.5 up to 67.5 bits as 67 bit factors.
But there should be about two or three 68 factors?

organization of p-1 factoring
- -----------------------------

A lot of factors of exponents between 10000 and 1000000 were found using
the new P-1 method. Is there a database which contains which exponent
were tested using which B1 and maybe a database od the save files?

reto
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------------------------------

Date: Fri, 25 Feb 2000 20:17:31 -0000
From: "Brian J. Beesley" <[EMAIL PROTECTED]>
Subject: Re: Mersenne: p-1 and trial factoring

<color><param>0100,0100,0100</param>On 25 Feb 00, at 15:23, Reto Keiser wrote:


<color><param>7F00,0000,0000</param>> Why can't we do first first the factorization up 
to n-2 bits (1/4) of the

> trial factoring time, then start the P-1 factoring up to 1/3 of the B1

> value, after this, we can complete the trial factoring process and at the

> end we complete the P-1 (using the save file od intermediate file). (the

> parameters can be optimized)


</color>This sounds fairly sensible. However, this entails splitting the 
factoring part into fairly small sub-assignments, which may cause 
unneccessary complications with the server. Also, trial factoring and 
P-1 are quite different from the point of view of system requirements 
- - trial factoring uses very little memory (in practice it runs almost 
entirely in the L1 cache) whereas P-1 is actually more of a memory 
hog than LL testing. So I suspect we want some bias towards early 
trial factoring rather than P-1.


<color><param>7F00,0000,0000</param>> until now >210 factors are found for 
10megadiginumbers and more than 280

> exponents were factored up to 68 bits. Some (about 7) 67 digit factors

> were found but none with 68 bits.


</color>This is likely to be a statistical anomoly. A sample size of 7 is a 
bit small to condemn the data as biased.


<color><param>7F00,0000,0000</param>> A lot of factors of exponents between 10000 and 
1000000 were found using

> the new P-1 method. Is there a database which contains which exponent were

> tested using which B1 and maybe a database od the save files?


</color>Yes - I think we need this database - with or without savefiles, it's 
a waste of effort to inadvertently duplicate work done before. Since 
P-1 is deterministic (like trial factoring, but unlike Pollard's rho 
or ECM) you should get the same result every if you use the same 
limits on the same exponent.


If anyone has any data to contribute, I'd be willing to assemble & 
publish the database. I also have adequate storage space on my anon 
ftp server for save files.



<nofill>
Regards
Brian Beesley
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------------------------------

Date: Fri, 25 Feb 2000 16:52:43 -0500
From: George Woltman <[EMAIL PROTECTED]>
Subject: Re: Mersenne: p-1 and trial factoring

Hi,

At 03:23 PM 2/25/00 +0100, Reto Keiser wrote:
>parallel use of p-1 and trial factoring
>---------------------------------------
>
>Why can't we do first first the factorization up to n-2 bits (1/4) of
>the trial factoring time, then start the P-1 factoring up to 1/3 of the
>B1 value, after this, we can complete the trial factoring process and at
>the end we complete the P-1 (using the save file od intermediate file).
>(the parameters can be optimized)

I can't see any flaws in your reasoning, although it would be a bit unwieldy
to implement.

>no 68 bit factors
>-----------------
>
>until now >210 factors are found for 10megadiginumbers and more than 280
>exponents were factored up to 68 bits.
>Some (about 7) 67 digit factors were found but none with 68 bits.

My database has:

33219661        73867482830512390441
33223387        83006905661336745889
33221387        123317319076102495049
33235409        128314644111933147703
33238463        131707491089550166169
33230671        139408728702078150121
33224957        193425473534465274127

That's 6 67-bit factors and 1 68-bit factor.  Not the expected 
distribution, but
nothing to be concerned about yet either.

>organization of p-1 factoring
>-----------------------------
>
>A lot of factors of exponents between 10000 and 1000000 were found using
>the new P-1 method. Is there a database which contains which exponent
>were tested using which B1 and maybe a database od the save files?

All exponents from 20000 to 110000 were done with B1=1M and B2=40M
Exponents from 110000 to 600000 (still in progress) were done with
B1=100K and B2=4M.  I still have the save files for exponents below 110000.
I think Alex has the save files for the larger exponents.

However, it must be pointed out that at some point you are better off switching
to ECM rather than expanding the P-1 bounds.  I'm not sure what that point is.

Regards,
George

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------------------------------

Date: Fri, 25 Feb 2000 15:27:09 -0800
From: "Simon J Rubinstein-Salzedo" <[EMAIL PROTECTED]>
Subject: Mersenne: Perfect numbers

Can someone please outline a proof as to why (2^p-1)(2(p-1)) is a perfect
number if 2^p-1 is prime?

2^6972593 - 1 is prime.
e^(i*pi) + 1 = 0.
This is the e-mail address of Simon Rubinstein-Salzedo.
When you read this e-mail, Simon will probably be at a math contest.
Don't forget to check Simon's website at http://www.albanyconsort.com/simon
Thanks
SJRS

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------------------------------

Date: Sat, 26 Feb 2000 02:35:15 +0100
From: =?iso-8859-1?Q?Ignacio_Larrosa_Ca=F1estro?= <[EMAIL PROTECTED]>
Subject: RE: Mersenne: Perfect numbers

A number N is perfect if an only if sigma(N)=2N, where the sigma function is
the sum of alldivisors of N, including 1 and N.

The sigma function verify:

i) sigma(p)=p+1, if p is prime
ii) sigma(p^n)=1+p+p^2+...+p^n=(p^(n+1)-p)/(p-1), if p is prime
iii) sigma(a�b)=sigma(a)�sigma(b), if gcd(a,b)=1 (it's a multiplicative
function)

Then, if N=2^(p-1)(2^p-1), with 2^p-1 prime 8a Mersenne prime), we have

sigma(N)=sigma(2^(p-1)(2^p-1))=sigma(2^(p-1))sigma(2^p-1)=((2^p-1)/(2-1))(2^
p-1+1)=
(2^p-1)2^p=2(2^(p-1))(2^p-1))=2N.

There is a partial converse: If  N is perfect AND EVEN, then
N=2^(p-1)(2^p-1), with 2^p-1 prime.
It is not proved the inexistence of perfect odd numbers, althought the
minimum cote is very high.

Un saludo,

Ignacio Larrosa Ca�estro
A Coru�a (Espa�a)
[EMAIL PROTECTED]

- ----- Original Message -----
From: Simon J Rubinstein-Salzedo <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, February 26, 2000 12:27 AM
Subject: Mersenne: Perfect numbers


> Can someone please outline a proof as to why (2^p-1)(2(p-1)) is a perfect
> number if 2^p-1 is prime?
>
> 2^6972593 - 1 is prime.
> e^(i*pi) + 1 = 0.
> This is the e-mail address of Simon Rubinstein-Salzedo.
> When you read this e-mail, Simon will probably be at a math contest.
> Don't forget to check Simon's website at
http://www.albanyconsort.com/simon
> Thanks
> SJRS
>
> _________________________________________________________________
> Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm
> Mersenne Prime FAQ      -- http://www.tasam.com/~lrwiman/FAQ-mers
>

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------------------------------

Date: Fri, 25 Feb 2000 21:01:59 EST
From: [EMAIL PROTECTED]
Subject: Mersenne: Prime95... what else:?

Someone's sending mail to the list that makes its background appear red again 
(in AOL 3.0). Hrm.

<<1)To be sure PRIME 95 saves it's work when I need to reboot Windoze 98, I
bring PRIME 95 to the surface, hit Escape, and wait till the program
resonds [Execution Halted].  Does re-booting from this point without
closing PRIME95 save up-to-the-second work that has been done to a file
which is continued next time PRIME 95 loads?  >>

Just shut down your computer normally. Win95 or Win98 sends a signal to all 
programs that a shutdown is occuring, and Prime95 automatically saves 
everything. Set it up as a Win95 service, no icon, and you can "set it and 
forget it".

<<2) Given the same "P-90 Computer Years"  as the next three Top Producers
and comparing my COMPONENTS TESTED (third column below) why is it my
computer turns up as such a slacker?  ...This isn't golf.  >>

Pro'lly because you turn your computer off. An efficient person who works two 
hours a day will get less done than a slacker who works 18 hours a day. That 
is, unless the slacker is REALLY lazy, or non-Intel. :-P  Heh heh.

Stephan "Property of Bill and Andy" Lavavej
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------------------------------

Date: Sat, 26 Feb 2000 00:33:49 EST
From: "Nathan Russell" <[EMAIL PROTECTED]>
Subject: Mersenne: A couple quick questions

    I just joined GIMPS (now 6% done testing a number with exponent just 
short of 10M if it makes a difference) and I have been looking into the 
theory behind Mersenne primes.
    Can anyone show me or at least point me to a webpage with the proof that 
the exponent of a Mersenne prime must be prime?  How about a proof that the 
LL test works?  I have had math through DiffEq I.  It is intuitively obvious 
to me that every Mersenne number with even composite exponent will be found 
by the formula M(p) = 4M(p-2)+3.
Since M(2)=3 is a multiple of 3, all these numbers will also be multiples, 
and therefore composite.  However, I can't understand why this is true of 
numbers whose exponents have higher
    This is particularly easy to see when the numbers are written in binary. 
  Since it is difficult to hand-compute the factors of Mersenne composites 
much above 1023, I cannot easily search for patterns in higher Mersenne 
numbers with composite exponent that has no factor of 2.

A completely unrelated question: Why, on the PrimeNet stats summery page, 
are far more numbers listed as "finished LL" than as "available for 
doublecheck"?  Does this simply mean that some numbers do not require 
doublechecking because they were turned in by a proven computer?  Or have 
they been already double-checked and turned in since the page was last 
updated?

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------------------------------

Date: Sat, 26 Feb 2000 10:33:35 +0100
From: "Hans-Martin Anger" <[EMAIL PROTECTED]>
Subject: Re: Mersenne: A couple quick questions

let m=2^(a*b)-1.
then 2^a-1 is a divisor of m.

example:
2^35-1=(2^5-1)*(2^30+2^25+2^20+2^15+2^10+2^5+1)

general:

2^(a*b)-1 = (2^a-1)*(2^((b-1)*a)+2^((b-2)*a)+...+2^(1*a)+1)

regards
Martin

- -----Urspr�ngliche Nachricht-----
Von: Nathan Russell <[EMAIL PROTECTED]>
An: <[EMAIL PROTECTED]>
Gesendet: Samstag, 26. Februar 2000 06:33
Betreff: Mersenne: A couple quick questions


>     I just joined GIMPS (now 6% done testing a number with exponent just
> short of 10M if it makes a difference) and I have been looking into the
> theory behind Mersenne primes.
>     Can anyone show me or at least point me to a webpage with the proof
that
> the exponent of a Mersenne prime must be prime.
>============ snip ===================


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------------------------------

Date: Sun, 27 Feb 2000 02:55:21 -0800
From: Paul Leyland <[EMAIL PROTECTED]>
Subject: RE: Mersenne: p-1 and trial factoring

BJB wrote:

> Yes - I think we need this database - with or without savefiles,
> it's a waste of effort to inadvertently duplicate work done before.
> Since P-1 is deterministic (like trial factoring, but unlike
> Pollard's rho or ECM) you should get the same result every if you use
> the same limits on the same exponent. 

If your implementations of rho and ECM are not deterministic, I suggest that
you reimplement and/or get a working machine.

Running rho with the same iterated function and starting value on the same
exponent should give the same result every time.

Running ecm with the same limits and the same curve on the same exponent
should likewise give you the same result every time.

Indeed, rerunning a new implementation with the same parameters as an old
and (presumably) working implementation is one of the important ways of
debugging and tuning the new version.


The degree of freedom in choosing an elliptic curve for ECM is probably what
you're hinting at.  I'd suggest that a database of number of curves at run
each B1/B2 limit is still useful.  George keeps such a database for small
exponents.


Paul


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